The ZnCl₂ solution have a molarity of 1.33 M.
Explanation:
We have the following chemical reaction:
Zn (s) + CuCl₂ (aq) → ZnCl₂ (aq) + Cu (s)
number of moles = mass / molar weight
number of moles of Zn = 25 / 65.4 = 0.38 moles
From the chemical equation we see that 1 moles of Zn produces 1 mole of ZnCl₂, so 0.38 moles of Zn will produce 0.38 moles of ZnCl₂.
molarity = number of moles / volume (L)
molarity of the ZnCl₂ solution = 0.38 / 0.285 = 1.33 M
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Use the ideal gas law:
PV = nRT
so, T = PV / nR
n=0.5
V= 120 dm^3 = 120 L (1 dm^3 = 1 L)
R = 1/12
P = 15,000 Pa = 0.147 atm (1 pa = 9.86 10^{-6} )
Put the values:
T = PV / nR
T = (0.147) (120) / (0.5) (1/12)
T= 426 K
