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vivado [14]
3 years ago
7

Pls help! Describe ionic and covalent bonding. Give an example of each

Chemistry
1 answer:
ankoles [38]3 years ago
6 0

Answer:

Example of ionic bonds— Sodium chloride and calcium oxide. Example of covalent bond— Water, carbon

Explanation:

ionic bond, also called electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound. Such a bond forms when the valence (outermost) electrons of one atom are transferred permanently to another atom.

A covalent bond consists of the mutual sharing of one or more pairs of electrons between two atoms. These electrons are simultaneously attracted by the two atomic nuclei. A covalent bond forms when the difference between the electronegativities of two atoms is too small for an electron transfer to occur to form ions.

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What is wrong with the notation 1s22s22p63s23p63d104s24p2 for germanium (atomic number 32)?
Vaselesa [24]
<span>The notation is not written in the correct order as the 4s subshell should appear before the 3d subshell.
</span>The correct order in an electron configuration would be: 
1s , 2s , 2p , 3s , 3p , 4s , 3d , 4p , 5s , 4d , 5p , 6s , 4f , 5d , 6p ,..
So, for germanium the electronic configuration should be;
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p² 



3 0
3 years ago
Which composition of water moves to begin a deep water current
jasenka [17]
Cold and high salinity. Hope this helps :)
4 0
3 years ago
Read 2 more answers
At 298 K the standard enthalpy of combustion of sucrose is -5645 kJ/mol and the standard reaction Gibbs energy is -5798 kJ/mol.
natka813 [3]

Explanation:

The given data is as follows.

             T = 298 K,          \Delta H^{o} = -5645 kJ/mol

          \Delta G^{o} = -5798 kJ/mol

Relation between \Delta H and \Delta G are as follows.

          \Delta G^{o} = \Delta H^{o} - T \Delta S^{o}    

             -5798 kJ/mol = -5645 kJ/mol - 298 \times \Delta S^{o}

                       -153 kJ/mol = -298 \times \Delta S^{o}

                    \Delta S^{o} = 0.513 kJ/mol K

Now, temperature is 37^{o}C = (37 + 273) K = 310 K

Since,        \Delta G = \Delta H^{o} - T \Delta S^{o}

                            = -5645 kJ/mol - 310 K \times 0.513 kJ/mol K

                            = (-5645 kJ/mol - 159.03 kJ/mol)

                            = -5804.03 kJ/mol

As, change in Gibb's free energy = maximum non-expansion work

            \Delta G = \Delta G_{310 K} - \Delta G_{298 K}

                           = -5804.03 kJ/mol - (-5798 kJ/mol)

                           = -6.03 kJ/mol

Therefore, we can conclude that the additional non-expansion work is -6.03 kJ/mol.

5 0
3 years ago
How many moles of ammonia are in 1.20 x10 25 molecules of ammonia?
aleksley [76]
The  moles    of  ammonia  in  1.20  x10^25  molecules  of  ammonia  is  calculated  as  follows

by  use   of   Avogadro    constant

1moles =  6.02  x10^23

what  about    1.20  x10^25  moles

by  use  of  cross  multiplication

=   1 mole   x  (  1.20  x10^25)  /(   6.02  x10^23)   =  19.93  moles   
7 0
3 years ago
1. What are physical and chemical properties of metals, nonmetals, and metalloids?​
Yuri [45]
Metals are dense, shiny, good conductors of heat and electricity, and easily lose electrons in chemical reactions. Nonmetals are not dense, dull, do not conduct heat and electricity, and tend to gain electrons. Metalloids are elements that have properties of both metals and nonmetals.

Have a good day!
8 0
4 years ago
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