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mr_godi [17]
3 years ago
8

An object falls freely for 25 seconds, what is the velocity after the 25 seconds ?

Physics
1 answer:
Andrei [34K]3 years ago
5 0
The acceleration of gravity on Earth is 9.8 m/s² downward.
This means that gravity adds 9.8 m/s downward to the speed
of a freely falling object every second.

So after 25 sec, it's falling (25 x 9.8m/s) = 245 m/s faster than
it was falling at the beginning of the 25 seconds.

If it dropped from rest (no speed), then its velocity
after 25 seconds is 245 m/s downward. 
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Answer it pls!!!!!!!!!!!
Archy [21]

Answer:

Fractional error = 0.17

Percent error = 17%

F = 112 ± 19 N

Explanation:

Plug in the values to find the force:

F = (3.5 kg) (20 m/s)² / (12.5 m) = 112 N

Find the fractional error:

ΔF/F = Δm/m + 2Δv/v + Δr/r

ΔF/F = 0.1/3.5 + 2(1/20) + 0.5/12.5

ΔF/F = 0.17

Multiply by 100% to find the percent error:

ΔF/F × 100% = 17%

Solve for the absolute error:

ΔF = 0.17 × 112 N = 19 N

Therefore, the force is:

F = 112 ± 19 N

8 0
3 years ago
A real spring does not oscillate forever. Instead, it eventually comes to a stop. Does this violate the law of conservation of e
ss7ja [257]
It does not violate the law of conservation of energy. The oscillation stops when the energy is lost and the energy is lost because it becomes heat that is created by the air resistance and many other forces found in the surrounding of the oscillating spring.
5 0
3 years ago
Which vehicle has the LEAST kinetic energy? 18-wheeler, minivan, car, or bike?
Whitepunk [10]

We can make pretty good guesses for their masses, but kinetic energy also depends on their speeds, which we don't know, and may change.

As an example ... If the truck, the van, the car, and the bike are all parked at the mall, then a scampering mouse has more kinetic energy than all of them combined.

As the question stands, no answer is possible.

7 0
3 years ago
A basketball player of height 2.40 m is standing 2.60 m in front of a convex spherical mirror of radius of curvature 4.00 m. Det
IrinaVladis [17]

Answer:

The size of the image is 1.04 m.

Explanation:

Given that,

Height of object = 2.40 m

Distance of object = 2.60 m

Radius of curvature =4.00 m

Focal length f=\dfrac{R}{2}=\dfrac{4.00}{2}=2.00

We need to calculate the image distance

Using mirror formula

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

\dfrac{1}{v}=\dfrac{1}{2.00}+\dfrac{1}{2.60}

\dfrac{1}{v}= \dfrac{23}{26}

v=1.13\ cm

We need to calculate the height of the image

Using formula of magnification

m=\dfrac{h'}{h}=-\dfrac{v}{u}

Put the value into the formula

\dfrac{h'}{2.40}=-\dfrac{1.13}{-2.60}

h'=\dfrac{1.13}{2.60}\times2.40

h'=1.04\ m

Hence, The size of the image is 1.04 m

8 0
3 years ago
The maximum allowable resistance for an underwater cable is one hundredth of an ohm per
Studentka2010 [4]

Answer:

A = 1.54 x 10⁻⁵ m² = 15.4 mm²

Explanation:

The resistance of a wire can be given by the following formula:

R = \frac{\rho L}{A}\\\\A = \frac{\rho L}{R} = \frac{\rho}{\frac{R}{L} }

where,

A = smallest cross-sectional area = ?

ρ = resistivity of copper = 1.54 x 10⁻⁸ Ωm

\frac{R}{L} = resistance per unit length of wire = 0.001 Ω/m

Therefore,

A = \frac{1.54\ x\ 10^{-8}\ \Omega m}{0.001\ \Omega/m}

<u>A = 1.54 x 10⁻⁵ m² = 15.4 mm²</u>

6 0
3 years ago
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