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mr_godi [17]
3 years ago
8

An object falls freely for 25 seconds, what is the velocity after the 25 seconds ?

Physics
1 answer:
Andrei [34K]3 years ago
5 0
The acceleration of gravity on Earth is 9.8 m/s² downward.
This means that gravity adds 9.8 m/s downward to the speed
of a freely falling object every second.

So after 25 sec, it's falling (25 x 9.8m/s) = 245 m/s faster than
it was falling at the beginning of the 25 seconds.

If it dropped from rest (no speed), then its velocity
after 25 seconds is 245 m/s downward. 
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Answer:

V1 = 15m/s[45o E of N.] = 45o N. of E.

V2 = 18m/s[5o N. of E.].

Vr = 15m/s[45o] + 18m/s[5o].

Vr = 15*Cos45+15*sin45 + 18*Cos5+18*sin5.

Vr = (10.61+10.61i) + (17.93+1.57i) = 28.54 + 12.18i.

Magnitude = sqrt(28.54^2 + 12.18^2) =

Tan A = Y/X = 12.18/28.54 = 0.42887. A =

0  2

posted by Henry

Apr 8, 2017

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Explanation:

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