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Andrew [12]
3 years ago
10

Water ia boled at 1 at pressure in a coffe aker equpped with an immension-type electric heating element. The coffee maker intial

ly contains 1 kg of water. Once boiling started, it is observed that half of he water in the coffee maker evaporated in 10 minutes the heat loss from the cofee maker is negigible, the power rating of the heating element is: a)-1.9kw b)-16 kw c)-0.8 kW d)-2.2 kw e)-3.8KW
Physics
1 answer:
tresset_1 [31]3 years ago
4 0

-- Water cannot be boled.

-- There is no such thing as a coffe aker.

-- There is no such thing as an immension-type heating element.

Be that as it may, and it very likely still is, as it were . . .

-- The latent heat of vaporization of water at 100°C is about 2250 kilo-joules per kg.

-- To evaporate half of the kg of water in the coffee maker requires 1125 kJ of heat energy.

-- To supply that amount of heat energy over a period of 10 minutes (600 seconds), it must be supplied at a rate of

(1,125,000 Joules / 600 seconds) = 1,875 joules/second.

-- That's 1,875 watts, or <em>1.875 kilowatts</em>.

-- <em>Choice-a</em> is the choice when the solution is rounded.

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The law of conservation of energy

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What do you know about water
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Explanation:

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3 years ago
Calculate the percentage of an iceberg submerged beneath the surface of the ocean given that the density of ice is 916.3kg/m3 an
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Answer:

The percentage of an iceberg submerged beneath the surface of the ocean = 89.67%

Explanation:

Let V be the total volume of the iceberg

Let x be the volume of iceberg submerged

According to Archimedes principle,

weight of the iceberg = weight of the water displaced (that is, weight of x volume of water)

Weight of the iceberg = mg= ρ(iceberg) × V × g

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We then have

ρ(iceberg) × V × g = ρ(fluid) × x × g

(x/V) = ρ(iceberg) ÷ ρ(fluid) = 916.3 ÷ 1021.9 = 0.8967 = 89.67%

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6 0
2 years ago
If the resistance of a circuit increases, that means that the current has to
Gnoma [55]

Answer:

If resistance increases current decreases.

Explanation:

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4 0
3 years ago
A 35.9 g mass is attached to a horizontal spring with a spring constant of 18.4 N/m and released from rest with an amplitude of
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Answer:

7.74m/s

Explanation:

Mass = 35.9g = 0.0359kg

A = 39.5cm = 0.395m

K = 18.4N/m

At equilibrium position, there's total conservation of energy.

Total energy = kinetic energy + potential energy

Total Energy = K.E + P.E

½KA² = ½mv² + ½kx²

½KA² = ½(mv² + kx²)

KA² = mv² + kx²

Collect like terms

KA² - Kx² = mv²

K(A² - x²) = mv²

V² = k/m (A² - x²)

V = √(K/m (A² - x²) )

note x = ½A

V = √(k/m (A² - (½A)²)

V = √(k/m (A² - A²/4))

Resolve the fraction between A.

V = √(¾. K/m. A² )

V = √(¾ * (18.4/0.0359)*(0.395)²)

V = √(0.75 * 512.53 * 0.156)

V = √(59.966)

V = 7.74m/s

8 0
3 years ago
Read 2 more answers
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