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Andrew [12]
3 years ago
10

Water ia boled at 1 at pressure in a coffe aker equpped with an immension-type electric heating element. The coffee maker intial

ly contains 1 kg of water. Once boiling started, it is observed that half of he water in the coffee maker evaporated in 10 minutes the heat loss from the cofee maker is negigible, the power rating of the heating element is: a)-1.9kw b)-16 kw c)-0.8 kW d)-2.2 kw e)-3.8KW
Physics
1 answer:
tresset_1 [31]3 years ago
4 0

-- Water cannot be boled.

-- There is no such thing as a coffe aker.

-- There is no such thing as an immension-type heating element.

Be that as it may, and it very likely still is, as it were . . .

-- The latent heat of vaporization of water at 100°C is about 2250 kilo-joules per kg.

-- To evaporate half of the kg of water in the coffee maker requires 1125 kJ of heat energy.

-- To supply that amount of heat energy over a period of 10 minutes (600 seconds), it must be supplied at a rate of

(1,125,000 Joules / 600 seconds) = 1,875 joules/second.

-- That's 1,875 watts, or <em>1.875 kilowatts</em>.

-- <em>Choice-a</em> is the choice when the solution is rounded.

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Answer:

C1/C2 = 0.213 or C2/C1 = 4.68

Explanation:

Please refer to the attached image for step by step explanation.

5 0
4 years ago
If a cylindrical space station 275 m in diameter is to spin about its central axis, at how many revolutions per minute (rpm) mus
sergij07 [2.7K]

The centripetal acceleration is responsible for the artificial gravity because the acceleration of an object moving in constant circular motion causing from net external force is called centripetal acceleration. It defines to the center or seeking the center.

Given the following:

Cylindrical space station diameter           = 275 meters; 137.5 meters for the radius

Standard gravity                                       = 9.80665 m/s²

 

Using the formula:

w² x r =g

w² = g / r

w² = 9.80665 m/s² / 137.5 m

w² = 9.80665 m/s² / 137.5 m

w² = 0.0713 s²

Then take the roots

w = 0.267 this is radians per second / 2 x (3.1416 which is the pi)

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w = 7.08 x 10⁻⁴ revolutions per minute

4 0
3 years ago
A 1.50-V battery supplies 0.414 W of power to a small flashlight. If the battery moves 4.93 1020 electrons between its terminals
slamgirl [31]

Answer:

2.86×10⁻¹⁸ seconds

Explanation:

Applying,

P = VI................ Equation 1

Where P = Power, V = Voltage, I = Current.

make I the subject of the equation

I = P/V................ Equation 2

From the question,

Given: P = 0.414 W, V = 1.50 V

Substitute into equation 2

I = 0.414/1.50

I = 0.276 A

Also,

Q = It............... Equation 3

Where Q = amount of charge, t = time

make t the subject of the equation

t = Q/I.................. Equation 4

From the question,

4.931020 electrons has a charge of (4.931020×1.6020×10⁻¹⁹) coulombs

Q = 7.899×10⁻¹⁹ C

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t =  7.899×10⁻¹⁹/0.276

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5 0
3 years ago
A glider with mass 0.24 kg sits on a frictionless horizontal air track, connected to a spring of negligible mass with force cons
shepuryov [24]

Answer:

v=2.556m/s

Explanation:

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4 0
3 years ago
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At the instant you release it, or keep your hands on it but stop pushing,
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6 0
3 years ago
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