Which point lies on the line: y – 4 = -3(x + 2)?
1 answer:
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Answer:
x = 2
Step-by-step explanation:
For quadratic ax^2 +bx +c, the axis of symmetry is x = -b/(2a).
Here, we have a=2, b=-8, so the axis of symmetry is ...
x = -b/(2a) = -(-8)/(2(2)) = 8/4
x = 2
Answer:
Step-by-step explanation:
First create an equation in slope-intercept form, y = mx + b. To do this, find the rate of change or slope (m), and the y-intercept (b).
Using two pairs, (-7, -3) and (-8, -4),
m = 1
To find b, substitute m = 1, x = -7 and y = -3 into y = mx + b.
Thus:
-3 = (1)(-7) + b
-3 = -7 + b
-3 + 7 = b
4 = b
b = 4.
Replace y with f(x), m with 1 and b with 4 in y = mx + b.
The function would be: