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3 years ago

Someone help me with this ASAP

Chemistry

2 answers:

dolphi86 [110]3 years ago

8 0

Convection i believe

ZanzabumX [31]3 years ago

6 0

Answer:

First bone

Explanation:

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Cual es el volumen de la solución de hcl la cual se preparo con 3 gramos de soluto (k) al 14%

Elena-2011 [213]

Answer:

from which language this belongs to

3 0

2 years ago

The volume density of atoms for a bcc lattice is 5 x 1026 m-3. Assume that the atoms are hard spheres with each atom touching it

ollegr [7]

Explanation:

It is known that for a body centered cubic unit cell there are 2 atoms per unit cell.

This means that volume occupied by 2 atoms is equal to volume of the unit cell.

So, according to the volume density

$5 \times 10^{26} atoms = 1 [tex]m^{3}$

2 atoms = $\frac{1 m^{3}}{5 \times 10^{26} atoms} \times 2 atoms$

= $4 \times 10^{-27} m^{3}$

Formula for volume of a cube is $a^{3}$ . Therefore,

Volume of the cube = $4 \times 10^{-27} m^{3}$

As lattice constant (a) = $(4 \times 10^{-27} m^{3})^{\frac{1}{3}}$

= $1.59 \times 10^{-9} m$

Therefore, the value of lattice constant is $1.59 \times 10^{-9} m$ .

And, for bcc unit cell the value of radius is as follows.

r = $\frac{\sqrt{3}}{4}a$

Hence, effective radius of the atom is calculated as follows.

r = $\frac{\sqrt{3}}{4}a$

= $\frac{\sqrt{3}}{4} \times 1.59 \times 10^{-9} m$

= $6.9 \times 10^{-10} m$

Hence, the value of effective radius of the atom is $6.9 \times 10^{-10} m$ .

3 0

2 years ago

The volume of the granite as

Trava [24]

The volume of the granite as determined by water displacement is 9.35 mL. This value in cm³ is 9.35cm³.

<h3>How to calculate volume in cm³?</h3>

The conversion factor of mL and cm³ is given as follows: 1 mL = 1 cm³

According to this question, the volume of the granite as determined by water displacement is 9.35 mL.

This value in cm³ can be converted as follows:

9.35mL × 1 = 9.35cm³

Therefore, the volume of the granite as determined by water displacement is 9.35 mL. This value in cm³ is 9.35cm³.

Learn more about volume at: brainly.com/question/1578538

#SPJ1

8 0

1 year ago

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Svet_ta [14]

Answer:

$V_1=23.3~mL$

Explanation:

In this case, we have a dilution problem. We have to remember that in the dilution procedure we go from a solution with higher concentration to a solution with lesser concentration. Therefore we have to start with the dilution equation:

$C_1*V_1=C_2*V_2$

Now we can identify the variables:

$C_1=~1.475_M$

$V_1=~?$

$C_2=~0.1374_M$

$V_2=~250.0~mL$

If we plug all the values into the equation:

$1.475_M*V_1=0.1374_M*250.0~mL$

And we solve for $V_1$ :

$V_1=\frac{0.1374_M*250.0~mL}{1.475_M}$

$V_1=23.3~mL$

I hope it helps!

8 0

2 years ago

From the balanced reaction:

Lelu [443]

Answer:

The mass of O₂ that will be needed to burn 36.1 g B₂H₆ is 125.29 g.

7 0

2 years ago