Determining a car's depreciation over a ten year period is considered a bivariate.
<h3>What is a bivariate?</h3>
A Bivariate data is made up of two variables that are observed against each other. In determining the deprecation of a car, the cost of the car is observed against the passage of time and the depreciation factor.
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Answer:
(e) csc x − cot x − ln(1 + cos x) + C
(c) 0
Step-by-step explanation:
(e) ∫ (1 + sin x) / (1 + cos x) dx
Split the integral.
∫ 1 / (1 + cos x) dx + ∫ sin x / (1 + cos x) dx
Multiply top and bottom of first integral by the conjugate, 1 − cos x.
∫ (1 − cos x) / (1 − cos²x) dx + ∫ sin x / (1 + cos x) dx
Pythagorean identity.
∫ (1 − cos x) / (sin²x) dx + ∫ sin x / (1 + cos x) dx
Divide.
∫ (csc²x − cot x csc x) dx + ∫ sin x / (1 + cos x) dx
Integrate.
csc x − cot x − ln(1 + cos x) + C
(c) ∫₋₇⁷ erf(x) dx
= ∫₋₇⁰ erf(x) dx + ∫₀⁷ erf(x) dx
The error function is odd (erf(-x) = -erf(x)), so:
= -∫₀⁷ erf(x) dx + ∫₀⁷ erf(x) dx
= 0
Step-by-step explanation:
- Perpendicular ( P ) = VT = 2
- Base ( b ) = PT
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Solution:
<u>Step-1: Find the slope of the line.</u>
Formula of slope: y₂ - y₁/x₂ - x₁
- y₂ - y₁/x₂ - x₁ = Slope
- => -2 - (-5)/-8 - (-4) = Slope
- => -2 + 5/-8 + 4 = Slope
- => 3/-4 = Slope
<u>Step-2: Use the point slope formula to determine the slope.</u>
Point slope form formula: y - y₁ = m(x - x₁)
- y - y₁ = m(x - x₁) = Equation of line
- => y - (-5) = -3/4{x - (-4)} = Equation of line
- => y + 5 = -3/4{x + 4} = Equation of line
- => y + 5 = -3x/4 - 3 = Equation of line
- => y = -3x/4 - 8 = Equation of line
The equation of the line is <u>y = -3x/4 - 8.</u>
Answer:
5
Step-by-step explanation:
The equation says y equals 5. I attached a graph below:
