Answer:
Simplify the expression.
i could not type in exponent so just open the screen shot
Step-by-step explanation:
i Hope it works
Answer:
x+2y=0
Step-by-step explanation:
answered
There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents
the number of deer y in that forest after x months? Round to the nearest thousandth.
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dribeiro
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Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
Final result :
4x3yz2 • (3x - 2y2)
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "z2" was replaced by "z^2". 4 more similar replacement(s).
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(((12•(x4))•y)•(z2))-((23x3•y3)•z2)
Step 2 :
Equation at the end of step 2 :
(((22•3x4) • y) • z2) - 23x3y3z2
