Answer:
mparing this value with the weight of the vehicle we see W₂> 1.6 10⁴ N
therefore the woman can lift the car
Explanation:
For this exercise on Pascal's principle, we use that the pressure in every incompressible liquid is the same
P₁ = P₂
the press is defined by
P = F / A
for the woman's side
the area of a circle is
A = π D₁² / 4
P₁ = W (4 /π d₁²)
for the car side
A₂ =π d₂²
P₂ = W₂ (4 /π d₂²)
we substitute in the first equation
W (4 /π d₁²) = W₂ 4 /π d₂²)
W / d₁² = W₂ / D₂²
W₂ = (d₂ / d₁)² W
the weight of the woman is
W = mg
we calculate
W₂ = (24/3)₂ 50 9.8
W₂ = 3,136 10⁴ N
when comparing this value with the weight of the vehicle we see
W₂> 1.6 10⁴ N
therefore the woman can lift the car
Force applied = F = 628 N
<span>Acceleration = a m/s² </span>
<span>Newton's 2nd law of motion : F = Ma </span>
<span> a = F/M -------- (1) </span>
<span>New mass of the crate = M1 = 3.8M kg </span>
<span>New acceleration = a1 = F/M1 = F/(3.8 M) ----- (2) </span>
<span>a1/a = {F/(3.8M)}/(F/M) = 1/3.8 = 10/38 = 5/19 ------- Answer</span>
Answer:
A-B-C
Explanation:
Depends if you have good taste.
Answer:
Gradient of the hill is 53.33m/km which is lesser than the 500 m/km. So, he will be able to climb the hill conveniently.
Explanation: Given that
Maximum gradient = 500 m/km
Total distance = 1.5 km
Starting elevation = 20 m
Final elevation = 100 m
Gradient = change in elevation/ total distance.
Now, substitute the values into the formula.
Gradient = (100m - 20m)/1.5km
= 80m/1.5km
= 53.33m/km
Gradient of the hill is 53.33m/km which is lesser than the 500 m/km. So, he will be able to climb the hill conveniently.