Speed =dist./time
=73.4/5
=14.68 km/hr
Answer:
The inside Pressure of the tank is 
Solution:
As per the question:
Volume of tank, 
The capacity of tank, 
Temperature, T' = 
= 299.8 K
Temperature, T = 
= 288.2 K
Now, from the eqn:
PV = nRT (1)
Volume of the gas in the container is constant.
V = V'
Similarly,
P'V' = n'RT' (2)
Also,
The amount of gas is double of the first case in the cylinder then:
n' = 2n
![\]frac{n'}{n} = 2](https://tex.z-dn.net/?f=%5C%5Dfrac%7Bn%27%7D%7Bn%7D%20%3D%202)
where
n and n' are the no. of moles
Now, from eqn (1) and (2):
Answer:Electoral Vote
Explanation:i did it before
Answer:
a) P =392.4[Pa]; b) F = 706.32[N]
Explanation:
With the input data of the problem we can calculate the area of the tank base
L = length = 10[m]
W = width = 18[cm] = 0.18[m]
A = W * L = 0.18*10
A = 1.8[m^2]
a)
Pressure can be calculated by knowing the density of the water and the height of the water column within the tank which is equal to h:
P = density * g *h
where:
density = 1000[kg/m^3]
g = gravity = 9.81[m/s^2]
h = heigth = 4[cm] = 0.04[m]
P = 1000*9.81*0.04
P = 392.4[Pa]
The force can be easily calculated knowing the relationship between pressure and force:
P = F/A
F = P*A
F = 392.4*1.8
F = 706.32[N]
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