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Cerrena [4.2K]
3 years ago
10

Which suspect is one who wrote the suicide note?

Physics
1 answer:
iris [78.8K]3 years ago
6 0
John Huddleston<3 :* luv u bby gurl
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During World War II, it was found that r, the radius of the shockwave produced during an atomic bomb explosion, depends on the e
cupoosta [38]

The atomic bomb explosion, depends on the energy released, W, the elapsed time, t, and the air density which altogether lead to the vaporisation of the contents within the mushroom cloud created.

<h3>What is an atomic bomb?</h3>

An atomic bomb is type of nuclear weapon that releases a vast amount of energy upon explosion in the form of fission reaction.

During an explosion of atomic bomb, a cloud of mushroom fire is formed which vaporises anything found within it. The extent of destruction depends on:

  • energy released, W,

  • the elapsed time, t, and

  • the air density.

Therefore, the atomic bomb explosion, depends on the energy released, W, the elapsed time, t, and the air density which altogether lead to the vaporisation of the contents within the mushroom cloud created.

Learn more about nuclear energy here:

brainly.com/question/24295936

#SPJ1

7 0
3 years ago
At the nose of a missile in flight, the pressure and temperature are 5.6 atm and 850°R, respectively. Calculate the density and
Contact [7]

To solve this problem we will apply the definition of the ideal gas equation, where we will clear the density variable. In turn, the specific volume is the inverse of the density, so once the first term has been completed, we will simply proceed to divide it by 1. According to the definition of 1 atmosphere, this is equivalent in the English system to

1atm = 2116lb/ft^2

The ideal gas equation said us that,

PV = nRT

Here,

P = pressure

V = Volume

R = Gas ideal constant

T = Temperature

n = Amount of substance (at this case the mass)

Then

\frac{n}{V} = \frac{P}{RT}

The amount of substance per volume is the density, then

\rho = \frac{P}{RT}

Replacing with our values,

\rho = \frac{5.6*2116}{1716*850}

\rho = 0.00812slug/ft^3

Finally the specific volume would be

v = \frac{1}{\rho}

v = 123ft^3/slug

6 0
3 years ago
Heat transfer between two substances is affected by specific heat and the
IgorLugansk [536]

The correct answer is D. Amount of time and area of physical contact between the substances.

Explanation:

Heat transfer refers to the flow of thermal energy or heat between two or more objects. This process involves multiple factors and implies heat from the hottest object goes to the coldest one until there is an equilibrium. To begin, heat transfer depends on the amount of thermal energy in the objects because objects must have a different amount of thermal energy for heat to flow.

Besides this, the amount of energy that flows depends on the time and the contact between the substances of objects. Indeed, objects need to be in contact or close to each other for heat to transfer, and the time needs to be enough for the process to occur. For example, if you place a pot over the fire just for a few seconds it is likely the heat transferred is minimal, which does not occur if you leave the pot more time. At the same time if the pot is in close contact with fire more heat will be transferred.-

6 0
4 years ago
Which of the following is a Nobel gas?<br> Ba2+<br> OA<br> OB. Ci<br> Kr<br> Ос.<br> Ca<br> D.
stepan [7]

Answer:

Kr

Explanation:

the element that is in group 18 is noble gasses. the elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og).

5 0
3 years ago
Point A of the circular disk is at the angular position θ = 0 at time t = 0. The disk has angular velocity ω0 = 0.17 rad/s at t
statuscvo [17]

Given that,

Angular velocity = 0.17 rad/s

Angular acceleration = 1.3 rad/s²

Time = 1.7 s

We need to calculate the angular velocity

Using angular equation of motion

\omega=\omega_{0}+\alpha t

Put the value in the equation

\omega=0.17+1.3\times1.7

\omega=2.38(k)\ m/s

We need to calculate the angular displacement

Using angular equation of motion

\theta=\theta_{0}+\omega_{0}t+\dfrac{\alpha t^2}{2}

Put the value in the equation

\theta=0+0.17\times1.7+\dfrac{1.3\times1.7^2}{2}

\theta=2.1675\times\dfrac{180}{\pi}

\theta= 124.18^{\circ}

We need to calculate the velocity at point A

Using equation of motion

v_{A}=v_{0}+\omega\times r

Put the value into the formula

v_{A}=0+2.38(k) \times0.2(\cos(124.18)i+\sin(124.18)j))

v_{A}=0.476\cos(124.18)j+0.476\sin(124.18)i

v_{A}=(-0.267j-0.393i)\ m/s

We need to calculate the acceleration at point A

Using equation of motion

a_{A}=a_{0}+\alpha\times r+\omega\times(\omega\times r)

Put the value in the equation

a_{A}=0+1.3(k)\times0.2(\cos(124.18)i+\sin(124.18)j)+2.38\times2.38\times0.2(\cos(124.18)i+\sin(124.18)j)

a_{A}=0.26\cos(124.18)i+0.26\sin(124.18)j+(2.38)^2\times0.2(\cos(124.18)i+\sin(124.18)j)

a_{A}=-0.146j-0.215i−0.636i+0.937j

a_{A}=0.791j-0.851i

a_{A}=-0.851i+0.791j\ m/s^2

Hence, (a). The velocity at point A is (-0.267j-0.393i)\ m/s

(b). The acceleration at point A is (-0.851i+0.791j)\ m/s^2

3 0
4 years ago
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