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Andre45 [30]
3 years ago
11

The force of air particles over an area is?

Physics
2 answers:
Arada [10]3 years ago
4 0
That's the "air pressure" everywhere on that area.
alex41 [277]3 years ago
4 0
<h3><u>Answer;</u></h3>

Air pressure

<h3><u>Explanation</u>;</h3>
  • <em><u>Pressure is the force that is applied over a unit of area. Air pressure is the weight of air molecules pressing down on the Earth. It is the force exerted by air particles on the earth's surface.</u></em>
  • The column of air extends to the top of the atmosphere.  As one move up increasing the altitude, the air pressure decreases since the air column is reduced.
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A 0.03 kg golf ball is hit off the tee at a speed of 34 m/s. The golf club was in contact with the ball for 0.003 s. What is the
Liula [17]

Answer:

The average force on ball by the golf club is 340 N.

Explanation:

Given that,

Mass of the golf ball, m = 0.03 kg

Initial speed of the ball, u = 0

Final speed of the ball, v = 34 m/s

Time of contact, \Delta t=0.003\ s

We need to find the average force on ball by the golf club. We know that the rate of change of momentum is equal to the net external force applied such that :

F=\dfrac{\Delta p}{\Delta t}\\\\F=\dfrac{mv-mu}{\Delta t}\\\\F=\dfrac{mv}{\Delta t}\\\\F=\dfrac{0.03\ kg\times 34\ m/s}{0.003\ s}\\\\F=340\ N

So, the average force on ball by the golf club is 340 N.

4 0
3 years ago
If a cart of 2 kg mass has a force of 8 newtons exerted on it, what is its acceleration?
maria [59]
This is an example of the Newton`s Second Law:
F = m * a
a = F / m
F = 8 N, m = 2 kg.
a = 8 N : 2 kg
Answer:
a = 4 m/s²
3 0
3 years ago
9. In a closed circuit made of a battery, a wire, a lightbulb, and a switch which part's main responsibility is allowing electri
Zielflug [23.3K]

Answer:

d

Explanation:

6 0
2 years ago
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The 3 important steps to a perfect forehand in tennis are : perfect swing, type of racket, and correct finish
Alex17521 [72]

Answer:

False

Explanation:

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3 0
2 years ago
A basketball player makes a jump shot. The 0.630-kg ball is released at a height of 1.80 m above the floor with a speed of 7.09
N76 [4]

mass of the ball m = 0.63 kg

initial height h = 1.8 m

final height h ' = 3.03 m

initial speed v = 7.09 m / s

final speed v ' = 4.21 m / s

Let the work done on the ball by air resistance W = ?

we know from law of conservation of energy ,

total energy at height h + work done by air = total energy at height h '

  mgh + ( 1/ 2) mv^ 2 + W = mgh ' + ( 1/ 2) mv'^ 2

0.630*9.8*1.8 + 0.63*7.09^2 + W = mgh ' + ( 1/ 2) mv'^ 2

From there you can find W

if there is negative sign indicates it work opposite direction to motion

6 0
2 years ago
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