All categories

3 years ago

Is not b please someone help me

Mathematics

1 answer:

Advocard [28]3 years ago

8 0

√j+√j+14=3√j+10
2√j+14=3√j+10
minus 2√j both sides
14=√j+10
minus 10 both sides
4=√j
squaer both sides
16=j

answer is D, 16

You might be interested in

If logb2=x and logb3=y, evaluate the following in terms of x and y:

Alja [10]

$log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x$

Solution:

Given that,

$log_b2 = x\\\\log_b3 = y --------(i)$

Use the following log rules

Rule 1: $log_b(ac) = log_ba + log_bc$

Rule 2: $log_b\frac{a}{c} = log_ba - log_bc$

Rule 3: $log_ba^c = clog_ba$

$a) log_b{162}$

Break 162 down to primes:

$162 = 2^1 \times 3^4$

$log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y$

Thus we get,

$log_b162 = x + 4y$

$b) log_b 324$

Break 324 down to primes:

$324 = 2^2 \times 3^4$

$log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y$

$c) log_b\frac{8}{9}$

By rule 2

$log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} = 3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} = 3x - 2y$

$d) \frac{log_b27}{log_b16}$

By rule 2

$\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} = 3y - 4x$

Thus the given are evaluated in terms of x and y

3 0

3 years ago

Plz help me find sides M and N round to the nearest tenth

Sergio [31]

Answer:

Step-by-step explanation:

gradpoint

6 0

2 years ago

Raul picks 20 flowers from his mother's garden. One fourth of them are purple. How many of the flowers are purple?

steposvetlana [31]

25% were purple and 30 percent another color

8 0

3 years ago

Read 2 more answers

Please help !!

shutvik [7]

Given:

The limit problem is:

$\lim_{x\to 3}(x^2+8x-2)$

To find:

The limit of the function by using direct substitution.

Solution:

We have,

$\lim_{x\to 3}(x^2+8x-2)$

Applying limit, we get

$\lim_{x\to 3}(x^2+8x-2)=(3)^2+8(3)-2$

$\lim_{x\to 3}(x^2+8x-2)=9+24-2$

$\lim_{x\to 3}(x^2+8x-2)=33-2$

$\lim_{x\to 3}(x^2+8x-2)=31$

Therefore, the correct option is D.

4 0

3 years ago

Over the summer, for every 14 Okra seeds Dana planted, 9 plants grew. If he planted 182 seeds, how many grew into plants?

vova2212 [387]

Simple...

you have: For every 14 seeds that Okra seeds Dana planted 9 of them grew; if he planted 182 seeds..how many grew?

Set up an equation...

$\frac{9}{14} = \frac{x}{182}$

Cross multiply....

14*x=14x

9*182=1638

14x=1638

$\frac{14x}{14} = \frac{1638}{14} =117
$

x=117

This means that, for 182 seeds planted, 117 of them grew to be plants.

Thus, your answer.

3 0

3 years ago

Read 2 more answers