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lesya692 [45]
4 years ago
12

Solve for x. 81 = 27^-x^-2

Mathematics
1 answer:
OleMash [197]4 years ago
4 0

Answer:

NO SOLUTION

Step-by-step explanation:

81=27^{-x^{-2}}

3^4=3^{3\left(-x^{-2}\right)}

4=3\left(-x^{-2}\right)

\:4=-\frac{3}{x^2}:\quad \mathrm{No\:Solution\:for}\:x\in \mathbb{R}

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You can get all the terms on one side, and then solve for x by any means:
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0 = 4x^2-11x-3

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4*-3 = -12

Now, look for two numbers that multiply to -12 and add to -11. Obviously these numbers are -12 and 1. (-12*1 = -12 and -12+1  = -11). Now, because of rules, you set it up in a Punnett square:

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So, you can use this to write an equivalent expression to the quadratic given:
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Answer:

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The equation of such a graph can be modeled as

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