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lina2011 [118]
3 years ago
14

What is the formula of the chromium(iii) complex that contains two ammonia and four thiocyanate (scn−) ligands?

Chemistry
1 answer:
Nonamiya [84]3 years ago
4 0
Answer is: formula of the complex is [Cr(NH₃)₂(SCN)₄<span>]</span>⁻<span>.
This complex has negative charge (-1) because chromium (central atom or metal) has oxidation number +3, first ligand ammonia has neutral charge and second ligand thiocyanate has negative oxidation number -1:
+3 + 2</span>·0 + 4·(-1) = -1.
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Answer:

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After that if we to multiply the avogadro number with it. So 3 *NA

Now u want only atom calculation then we have 2 molecule of oxygen then multiply it with 2 too.

So final claculation is =3*2*NA.

Explanation:

your welcome

brainlest PLEASEEEEEEE!

3 0
3 years ago
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