3 years ago

What is the formula of the chromium(iii) complex that contains two ammonia and four thiocyanate (scn−) ligands?

1 answer:

4 0

Answer is: formula of the complex is [Cr(NH₃)₂(SCN)₄]⁻.
This complex has negative charge (-1) because chromium (central atom or metal) has oxidation number +3, first ligand ammonia has neutral charge and second ligand thiocyanate has negative oxidation number -1:
+3 + 2·0 + 4·(-1) = -1.

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