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-Dominant- [34]
3 years ago
11

What best describes the battery in this picture? an electrolytic cell that has spontaneous half reactions

Chemistry
2 answers:
FrozenT [24]3 years ago
6 0

Answer:

multiple voltaic cells that have spontaneous half reactions

Explanation:

A battery is an electrochemical device that stores energy. This is connected to an electrical circuit, and chemical energy is transformed into electrical energy. All are similar in construction, each of these cells is composed of a positive and a negative electrode in addition to a separator. When the battery is discharged, an electrochemical change occurs between the different materials in the two electrodes. The electrons are transported between the positive and negative electrodes through an external circuit (light bulbs, starter motors, etc.)

nasty-shy [4]3 years ago
5 0

ok im not full sure man but i would say multiple voltaic cells that have spontaneous half reactions


     



                                          im sorry hope it helps

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The combustion of ethene in the presence of excess oxygen yields carbon dioxide and water: c2h4 (g) + 3o2 (g) → 2co2 (g) + 2h2o
meriva

Answer:

\boxed{-267.5}

Explanation:

You can calculate the entropy change of a reaction by using the standard molar entropies of reactants and products.

The formula is

\Delta_{r} S^{\circ} = \sum_n {nS_{\text{products}}^{\circ} - \sum_{m} {mS_{\text{reactants}}^{\circ}}}

The equation for the reaction is

                        C₂H₄(g) + 3O₂(g) ⟶ 2CO₂(g) + 2H₂O(ℓ)

ΔS°/J·K⁻¹mol⁻¹   219.5      205.0         213.6         69.9

\Delta_{r} S^{\circ} = (2\times213.6 + 2\times69.9) - (1\times219.5 + 3\times205.0)\\\\= 567.0 - 834.5 = \boxed{-267.5 \text{ J}\cdot\text{K}^{-1} \text{mol}^{-1}}

3 0
3 years ago
A Silty Clay (CL) sample was extruded from a 6-inch long tube with a diameter of 2.83 inches and weighed 1.71 lbs. (a) Calculate
inna [77]

Answer:

a) the wet density of the CL sample is 0.0453 lb/in³

b) the water content in the sample is 65.37%

c) the dry density of the CL sample is 0.0274 lb/in³

Explanation:

Given that;

diameter d = 2.83 in

length L = 6 in

weight m = 1.71 lbs

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V is volume of sample which is; π/4×d²×L

so p = M / π/4×d²×L

we substitute

p = 1.71 / (π/4 × (2.83)²× 6

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b)

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w =  (wet_weight - dry_weight) / dry_weight

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w = (140.9 - 85.2) / 85.2

w = 55.7 / 85.2

w = 0.6537 = 65.37%

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c)

dry density of the CL sample

to determine the dry density, we say;

Sd = p / ( 1 + w )

we substitute

Sd = 0.0453 / ( 1 + 0.6537)

Sd = 0.0453 /  1.6537

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therefore the dry density of the CL sample is 0.0274 lb/in³

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