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3 years ago

Which of the following is NOT the same?

Chemistry

2 answers:

emmainna [20.7K]3 years ago

6 0

They all equal the same thing

Inessa [10]3 years ago

4 0

All are the same. It equals to the same thing.

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When 10.0 grams of CH4 reacts completely with 40.0 grams of O2 such that there are no reactants left over, 27.5 grams of carbon

BARSIC [14]

Answer:

$\boxed{\text{27.4 g CO$_{2}$; 22.5 g H$_{2}$O}}}$

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.

M_r: 16.04 32.00 44.01 18.02

CH₄ + 2O₂ → CO₂ + 2H₂O

m/g: 10.0 40.0

1. Moles of CH₄

$\text{Moles of CH}_{4} = \text{10.0 g CH}_{4} \times \dfrac{\text{1 mol CH}_{4}}{\text{16.04 g CH}_{4}} = \text{0.6234 mol CH}_{4}$

2. Mass of CO₂

(i) Calculate the moles of CO₂

The molar ratio is (1 mol CO₂ /1 mol CH₄)

$\text{Moles of CO$_{2}$} = \text{0.6234 mol CH$_4$} \times \dfrac{\text{1 mol CO$_{2}$}} {\text{1 mol CH$_{4}$}} = \text{0.6234 mol CO$_{2}$}$

(ii) Calculate the mass of CO₂

$\text{Mass of CO$_{2}$} = \text{0.6234 mol CO$_{2}$} \times \dfrac{\text{44.01 g CO$_{2}$}}{\text{1 mol CO$_{2}$}} = \textbf{27.4 g CO$_{2}$}\\\\\text{The mass of carbon dioxide formed is } \boxed{\textbf{27.4 g CO$_{2}$}}$

3. Mass of H₂O

(i) Calculate the moles of H₂O

The molar ratio is (2 mol H₂O /1 mol CH₄)

$\text{Moles of H$_{2}$O}= \text{0.6234 mol CH}_{4} \times \dfrac{\text{2 mol H$_{2}$O}}{\text{1 mol CH$_{4}$}} = \text{1.247 mol H$_{2}$O}$

(ii) Calculate the mass of H₂O

$\text{Mass of H$_{2}$O} = \text{1.247 mol H$_{2}$O } \times \dfrac{\text{18.02 g H$_{2}$O}}{\text{1 mol H$_{2}$O}} = \textbf{22.5 g H$_{2}$O}\\\\\text{The mass of water formed is } \boxed{\textbf{22.5 g H$_{2}$O}}$

4 0

3 years ago

What is the volume in milliliters of 7.66 g of acetone

frosja888 [35]

In order to solve this, we have to know the density of acetone because it is the ratio of mass to volume. At a certain temperature and pressure, the density of a specific substance does not change. It is an intrinsic property of a substance with temperature and pressure dependence. Assuming this is in normal conditions, the density is equal to 0.784 g/mL. So, the volume would be equal to

Volume = Mass/Density
Volume = 7.66 g/0.784 g/mL = 9.77 mL

3 0

3 years ago

4. Which of the following elements does NOT belong to

marusya05 [52]

========== tellurium Te

7 0

3 years ago

In the solubility lab, sugar was the _____________ and water was the _______________.

Rasek [7]

In a homogenous mixture, sugar was the solute and water was the solvent. Solubility is the maximum amount of a solute that dissolves in a given amount of solvent at a constant temperature. Solutes are more soluble in a given solvent at higher temperatures. Therefore, when temperature increases, the solubility of the solute also increases.

<span>Moreover, the solubility of the substance ranges from infinitely soluble such as alcohol in water, to poorly soluble like silver chloride in water and the species that dissolves, the solute, can be another liquid, gas or a solid.</span>

4 0

3 years ago

Chlorine has 17 total electrons with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5. What are the first two quantum numbers for

nasty-shy [4]

Answer:

Chlorine has 17 total electrons with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5.

What are the first two quantum numbers for the six electrons in the 2p subshell?

Explanation:

The principal quantum number represents the shell number in which the electron is present.

It is represented with "n".

The next quantum number is the azimuthal quantum number.

It represents the shape of the orbital.

It has values from 0 to (n-1).

Its value depends on the principal quantum number.

Chlorine has 17 total electrons with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5.

For the six elecetrons in 2p subshell:

The first two quantum number values are the same and their values are:

n=2 , l=1.

7 0

3 years ago