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Sloan [31]
3 years ago
11

An 856 kg drag race car accelerates from rest to 105 km/h in .934s. What change in momentum does the force produce? Answer in un

its of kg • m/s
Part 2: what average force is exerted on the car? Answer in N
Physics
1 answer:
Ymorist [56]3 years ago
8 0

Hello!

Topic: Dinamic

Value to calculate: Force

First, we have to calculate the aceleration, for that, lets aplicate the formula:

\boxed{a=\frac{V-Vi}{t} }

How the final velocity is in km/h, we have to convert it on m/s, so:

m/s = km/h / 3,6

m/s = 105 / 3,6

m/s = 29,16

Then, lets replace formula according problem information:

a = \dfrac{29,16m/s-0m/s}{0,934s}

a =31,22\ m/s^{2}

Now, how we have the aceleration, lets applicate second law of newton for calculate the force produced:

\boxed{F=ma}

Replace and resolve it:

F = 856 kg * 31,22 m/s^2

F = 26724,32 kg * m/s^2

Then the force is of 26724,32 kg * m/s^2

But how we know an 1 kg * m/s^2 = 1 N

Then the average of the force is of <u>26724,32 N  </u>

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