Answer:
(a) 1.11sec
(b) 14.37m/s
(c) 31.78m
Explanation:
U = 18m/s, A = 37°, g = 9.8m/s^2
(a) t = UsinA/g = 18sin37°/9.8 = 18×0.6018/9.8 = 1.11sec
(b) Ux = UcosA = 18cos37° = 18×0.7986 = 14.37m/s
(c) R = U^2sin2A/g = 18^2sin2(37°)/9.8 = 324sin74°/9.8 = 324×0.9613/9.8 = 31.78m
Answer:
I = 5[amp]
Explanation:
Electrical power is defined as the product of voltage by current.
where:
P = power = 1150 [W]
V = voltage = 230 [V]
I = current [amp]
Now replacing:
![1150=230*I\\I=1150/230\\I=5[amp]](https://tex.z-dn.net/?f=1150%3D230%2AI%5C%5CI%3D1150%2F230%5C%5CI%3D5%5Bamp%5D)
A 15 [amp] fuse must be used. Always the fuse must be larger than the operating current, to protect the equipment from very high currents. above 15 [amp]
simple harmonic motion is a special type of periodic motion or oscillation where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacement.
Answer:
0 J
Explanation:
If it's at the same temperature then it doesn't need more heat. So it'd be 0 J since it's already at 0C.
Answer:
20 N.
Explanation:
The following data were obtained from the question:
Mass of block B (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Gravitational force (F) =..?
Force is simply defined as the product of mass and acceleration i.e
Force = mass (m) × acceleration (a)
F = ma
Thus, we can say that the gravitational force on block B will be the product of the mass of block B and acceleration due to gravity i.e
Gravitational force (F) = mass of block B (m) × acceleration due to gravity (g)
F = mg
Mass of block B (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Gravitational force (F) =..?
F = mg
F = 2 × 10
F = 20 N
The, the gravitational force exerted on block B is 20 N
