The speed at which the arrow would be launched is 133.42 m/s
The work-energy theorem asserts that the net work done applied by the forces on a particular object is equivalent to the change in its kinetic energy.
The equation for the work-energy theorem can be computed as:
where;
- Force (F) = 267 N
- distance Δx = 0.60 m
- mass (m) = 18 g
- speed (v) = ???
From the above equation, let make speed(v) the subject of the formula:
∴
v = 133.42 m/s
Learn more about the work-energy theorem here:
brainly.com/question/17081653
Answer:
'A ball is thrown straight up with an initial speed of 12 m/s_ What are the velocity and acceleration when it is at the top of its trajectory? Select all apply. v=12 mls a = 0 v =-12 mls a = 9.8 m/s2 Oa=-9.8 m/s2'
Explanation:
I look it up
Hope this helps
Answer:
B please give me brainlyest
Explanation:
Displacement can be zero so velocity is zero but the distance won’t be zero so speed won’t be zero
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