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2 years ago

9

What shape are the universe’s largest known galaxies? Question 12 options: A.elliptical B.spiral C.There aren't large galaxies!

D.irregular

1 answer:

jeka942 years ago

8 0

Elliptical shaped galaxies are the universe’s largest known galaxies.

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The wavelength of 10^15-Hz light is:

Vanyuwa [196]

Answer:

D.300nm

Explanation:

Wavelength = Speed of light / Frequency of light.....

where the speed of light is...(3 × 10^8)

Wavelength = (3 × 10^8)/(1 × 10^15)

Wavelength = 3 × 10^-7

;Wavelength = 300 × 10^-9

Hence its....300 nm

5 0

2 years ago

A 2.55 kg block starts from rest on a rough inclined plane that makes an angle of 60 degree with the horizontal. the coefficient

lorasvet [3.4K]

Answer:

Change in mechanical energy = work done by friction

so it is equal to

$W = -8.16 J$

Explanation:

As we know that change in mechanical energy must be equal to the work done by non conservative forces only

So here when block moves down the inclined plane then the work done by friction force is given as

$W = F.d$

here we have

$F = \mu F_n$

here we know that

$F_n = mg cos\theta$

so we have

$F_n = 2.55(9.81)(cos60)$

$F_n = 12.5 N$

Now the friction force on the block is given as

$F_f = \mu F_n$

$F_f = 0.25 \times 12.5$

$F_f = 3.13 N$

now work done by the friction is given as

$W = -(3.13)(2.61)$

$W = -8.16 J$

7 0

3 years ago

In a hydroelectric power plant, the shaft that connects the turbine to the generator has become inoperable. As a result, _____.

Lynna [10]

<span>Electricity will not be created.</span>

5 0

3 years ago

Read 2 more answers

What is frictional force?<br>

Ostrovityanka [42]

Answer:

<u><em>Frictional force refers to the force generated by two surfaces that contacts and slide against each other.</em></u>

~Hope this helps~ T^T

3 0

2 years ago

Consider a light, single-engine airplane such as the Piper Super Cub. If the maximum gross weight of the airplane is 7780 N, the

viva [34]

Answer:

V=19.08 m/s

Explanation:

Airplane gross weight w=7780 N

Airplane wing area S=16.6 m²

Air density p=1.2250 kg/m³

Maximum lift coefficient CL=2.1

To find

Stalling Speed

Solution

The equation to find stalling speed is given below

$W=(1/2)S_{area}(V_{Stalling-speed} )^{2} (P_{Air-density} )(C_{Lmax} )\\ so\\V_{Stalling-speed}=\sqrt{\frac{2W}{S_{area}*(P_{Air-density} )(C_{Lmax} )} }\\V_{Stalling-speed}=\sqrt{\frac{2*7780}{16.6*2.1*1.225} }\\ V_{Stalling-speed}=19.08 m/s$

5 0

2 years ago