Answer:
4/3
Explanation:
Shown in the picture attached
Answer:
hgt tdyrghgcderhgfe
Explanation:
rghttyhhhggggftttgf d's weyhvfswertfcdsettyhgftgdfvhgg fee e4y
Answer:
<h3>
2.3125m/s²</h3>
Explanation:
Using the equation of motion v² = u²+2aS
v is the final velocity = 120km/hr
120km/hr = 120 * 1000/1 * 3600 = 33.3m/s
u is the initial velocity = 0m/s
a is the acceleration
S is the distance covered = 240m
On substituting the given parameters
33.3² = 0²+2a(240)
33.3² = 480a
1110 = 480a
a = 1110/480
a = 2.3125m/s²
Hence the minimum constant acceleration that the aircraft require to be airborne after a takeoff run of 240 m is 2.3125m/s²
Answer:
Explanation:
Increase in gravitational potential energy = m x g x h
where m is mass , g is gravitational acceleration and h is height
In the first case when man climbs
increase in potential = 85 x g x h = 1.85 x 10³ J
gh = 21.7647
when dog climbs
increase in potential = 14.5 x g x h J
= 14.5 x 21.7647
= 315.6 J
The answer is:
Heat from the ankle is transferred to the ice pack.
The explanation:
-when the ice pack a lower temp than the ankle , it is very cool.
- and the injured ankle has a high temp or heat
and we know that Q transfer from the object with high heat to the object with the low temp So,
Heat will transfer from the ankle to the ice pack.
