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irinina [24]
3 years ago
10

PLEASE HELPPPPPPPP What is the average velocity of a train that goes 86 km in 1.3 hours?

Physics
1 answer:
olga_2 [115]3 years ago
5 0
The answer is:

V = d/t d = 86 km t = 1.3 hrs

V = 86 km/ 1.3 hrs

V = 66.15 km/ hrs

I hope this helps!!
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The temperature of the mantle varies greatly, from 1000° Celsius near its boundary with the crust, to 3700° Celsius

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3 years ago
Which of the following is a contact force?
shusha [124]

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7 0
3 years ago
A racing car on a straight accelerates from 100mph to 316 mph in three seconds what is the acceleration?
omeli [17]

Answer:

72mph/sec

Explanation:

The car goes from 100mph to 316mph in three seconds. Meaning it increases its speed by (316 - 100)mph in three seconds. That is 216 mph increase in three seconds. So, we divide the speed increase by the amount of time the increase occurred over. We get:

216mph / 3sec = 72mph/sec, our final answer

Hope it made sense. I would appreciate Brainliest, but no worries.

8 0
3 years ago
A farmer lifts his hay bales into the top loft of his barn by walking his horse forward with a constant velocity of 1 ft/s. Dete
Lesechka [4]

Answer:

The velocity of the hay bale is - 0.5 ft/s and the acceleration is 6.25\times 10^{- 3} ft/s^{2}

Solution:

As per the question:

Constant velocity of the horse in the horizontal, v_{x} = 1 ft/s

Distance of the horse on the horizontal axis, x = 10 ft

Vertical distance, y = 20 ft

Now,

Apply Pythagoras theorem to find the length:

20^{2} + 10^{2} = l^{2}

l^{2}= 500

Now,

x^{2} + y^{2} = 500                            (1)

Differentiating equation (1) w.r.t 't':

2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0

x\frac{dx}{dt} = - y\frac{dy}{dt}

where

\frac{dx}{dt} = Rate of change of displacement along the horizontal

\frac{dy}{dt} = Rate of change of displacement along the vertical

v_{x} = velocity along the x-axis.

v_{y} = velocity along the y-axis

xv_{x} = -yv_{y}

v_{y} = - 10\times \frac{1}{20} = - 0.5 ft/s

|v_{y}| = 0.5\ ft/s

Acceleration of the hay bale is given by the kinematic equation:

v_{y}^{2} = u_{y} + 2ay

(-0.5)^{2} =0 + 2ay

0.25 = 2ay

\frac{0.25}{2y} = a

a = \frac{0.25}{2\times 20} = 6.25\times 10^{- 3} ft/s^{2}

7 0
3 years ago
!!! 100 POINTS !!! PLEASE HELP !!!
hram777 [196]

Q1. Option 2: basketball


Q2: Newton's first law is <span>the </span>law<span> of inertia. </span>An object at rest stays at rest and an object in motion stays in motion.

<span>
</span>

<span>Q3. A basketball sitting on the floor stays there and a basketball rolling on court keeps on rolling.</span>

<span>
</span>

<span>Q4 Second law says acceleration is dependent upon net force and mass of the object.</span>


Q5. Basketball accelerates when a player tries to dunk it with both hands.


<span>Q6. Third law says f<span>or every action, there is an equal and opposite reaction.</span></span>

<span><span>
</span></span>

<span><span>Q7. As a player dribbles, the force the basketball hits the floor with is the same as the force from the floor on the ball. That is why the ball bounces back up in air.</span></span>

<span><span>
</span></span>


8 0
3 years ago
Read 2 more answers
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