It will not be carried to children ... because genetic defect can be carried to children, not the defect during his lifetime
Answer:
58.8 N
Explanation:
The normal force is calculated as equal to the perpendicular component of the gravitational force.
Thus; N = mg
We are given m = 6 kg
Thus;
N = 6 × 9.8
N = 58.8 N
Thus, magnitude of normal force on the rock = 58.8 N
Answer:
Vertical Height = 0.784 meter, Speed back at starting point = 10 m/s
Explanation:
Given Data:
V is the overall velocity vector,
and
are its initial vertical and horizontal components

To find:
Max Height
achieved
Calculation:
1) Using the
equation of motion, we know

2) In terms of gravity
height
and the vertical component of Velocity
.
3) As
as at maximum height the vertical component of velocity is zero maximum height achieved

putting values
4) 
5) As for the speed when it reaches back its starting point, it will have a speed similar to its launching speed, the reason being the absence of air friction (Air drag)
The kinetic energy K = 0.5 * m * v² must be equal to the potential energy U = m * g * h.
m mass
v velocity
h height
g = 9.81m/s²
The mass m cancels out:
0.5 * v² = g * h
Solve for height h and transform to distance traveled.
(sin (4°) = height / distance)
Answer:
The acorn hasn't hit the ground because it only falsl half of the branch distance from the ground
Explanation:
given information:
h =9.8
t =1 s
g = 9.8
the average speed
v = 1/2 gt²
= 1/2 (9.8) (1)²
= 4.8 m/s
the distance in 1s
h = v t
= 4.8 (1)
= 4.8 m
the acorn hasn't hit the ground because it only falsl half of the branch distance from the ground
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