In the lab you take 50.0 mL of a 40.0 M NaOH solution and then add water to it until it reaches the 500.0 mL mark of the flask.
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Answer:
Explanation:
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In this case, since the ionization of ammonia, which is a weak base, is written as:
We can see that the ammonium ion is the conjugate acid whereas the hydroxide ions the conjugate base; that is why we use the Henderson-Hasselbach equation to compute the pH, given the pKb of ammonia 4.75:
In such a way, for the given moles of ammonia, base, and those of ammonium chloride, conjugate acid form, we obtain:
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<u>Answer:</u> The temperature in degree Celsius is 301.31°C
<u>Explanation:</u>
To calculate the temperature, we use the equation given by ideal gas, which is:
P = pressure of the gas = 670 torr = 0.882 atm (Conversion factor: 1 atm = 760 torr)
V = volume of gas = 42.5 L
n = number of moles of gas = 0.795 mol
R = Gas constant =
T = temperature of gas
Putting values in above equation, we get:
Converting the temperature from kelvins to degree Celsius, by using the conversion factor:
Hence, the temperature in degree Celsius is 301.31°C