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Kazeer [188]
3 years ago
5

Which has the most momentum? (look at picture please)!!

Physics
1 answer:
aliina [53]3 years ago
6 0

Answer: the top one

Explanation: hope this helps

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Three children are riding on the edge of a merry-go-round that is 100 kg, has a 1.60-m radius, and is spinning at 20.0 rpm. The
Kay [80]

Answer:

25.33 rpm

Explanation:

M = 100 kg

m1 = 22 kg

m2 = 28 kg

m3 = 33 kg

r = 1.60 m

f = 20 rpm

Let the new angular speed in rpm is f'.

According to the law of conservation of angular momentum, when no external torque is applied, then the angular momentum of the system remains constant.

Initial angular momentum = final angular momentum

(1/2 x M x r^2 + m1 x r^2 + m2 x r^2 + m3 x r^2) x ω =

                                  (1/2 x M x r^2 + m1 x r^2 + m3 x r^2 ) x ω'

(1/2 M + m1 + m2 + m3) x 2 x π x f = (1/2 M + m1 + m3) x 2 x π x f'

( 1/2 x 100 + 22 + 28 + 33) x 20 = (1/2 x 100 + 22 + 33) x f'

2660 = 105 x f'

f' = 25.33 rpm

8 0
3 years ago
It is easier to climb up a slanted slope than a vertical slope
V125BC [204]

IT IS EASIER TO CLIMB A SLANTED SLOPE

3 0
3 years ago
Read 2 more answers
A body is thrown up with a velocity of 78.4 m per second.How high will it rise and how much time it will take to return to its p
a_sh-v [17]

Answer:

The maximum height reached by the body is 313.6 m

The time to return to its point of projection is 8 s.

Explanation:

Given;

initial velocity of the body, u = 78.4 m/s

at maximum height (h) the final velocity of the body (v) = 0

The following equation is applied to determine the maximum height reached by the body;

v² = u² - 2gh

0 = u² - 2gh

2gh = u²

h = u²/2g

h = (78.4²) / (2 x 9.8)

h = 313.6 m

The time to return to its point of projection is calculated as follows;

at maximum height, the final velocity becomes the initial velocity = 0

h = v + ¹/₂gt²

h = 0 + ¹/₂gt²

h =  ¹/₂gt²

2h = gt²

t² = 2h/g

t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 313.6}{9.8} }\\\\t = 8 \ s

4 0
3 years ago
Calculate the wavelength (in nm) of the blue light emitted by a mercury lamp with a frequency of 6.88 × 1014 Hz. The speed of li
Nezavi [6.7K]

Answer: 430 nm.

Explanation:

The relation of wavelength and frequency is:

Formula used : \nu=\frac{c}{\lambda}

where,

\nu = frequency =6.88\times 10^{14}Hz

\lambda = wavelength  = ?

c = speed of light = 3.00\times 10^{8}m/s

Now put all the given values in this formula, we get

6.88\times 10^{14}=\frac{3.00\times 10^{8}m/s}{\lambda}

\lambda=\frac{3.00\times 10^{8}m/s}{6.88\times 10^{14}}=0.43\times 10^{-6}m=430m        (1nm=10^{-9}m)

Thus the wavelength (in nm) of the blue light emitted by a mercury lamp is 430 nm.

6 0
3 years ago
According to the big bang theory, the universe is continually getting
oee [108]
The answer on Edge would be (A.)= Larger and Cooler ! I'm doing the same thing as y'all. Good luck everyone.

7 0
3 years ago
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