The speed of the sport car at the time of impact is 6.61 m/s.
<h3>What is the frictional force of the two cars?</h3>
Frictional force of the two cars = coefficient of kinetic frictin × mass × acceleration of gravity
= 0.8 × (2500+940) × 9.8
= 26970N
<h3>What is the acceleration of the skidded cars?</h3>
- As per Newton's second law of motion, force = mass × acceleration
- Acceleration= force / mass
= 26,970/3440
= 7.8 m/s²
<h3>What is the velocity of the sport car at the time of impact?</h3>
- As per Newton's equation of motion, V² - U² = 2aS
- Here, V = 0 m/s, a= -7.8 m/s², S= 2.8 m
- So, 0²-U²= 2×(-7.8)×2.8
=> U = √43.68
= 6.61 m/s
Thus, we can conclude that the speed of the sport car at the time of impact is 6.61 m/s.
Learn more about the Newton's equation of motion here:
brainly.com/question/8898885
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By firing electrons from a cathode gun at a known velocity through an electric field of a known strength, J.J Thomson was able to observe how much the field deflected the beam. With a mass-to-charge ratio calculated, he could determine that the mass of the electron was not significantly heavy (in fact almost nothing compared to the proton or neutron)
Answer: S<span>peed = 60.11 miles per hour
</span>
To solve for speed or rate use the formula for speed, s = d/t which means speed equals distance divided by time.
<span>speed = distance/time</span>
Answer:
Part a)
charge on each sphere is -1.95 micro coulomb
Part b)
For first sphere
excess charge
For second sphere
excess charge
For third sphere
absent charge
For third sphere
absent charge
Explanation:
Part a)
Since all the spheres are of identical size so the total charge of the sphere will divide equally on them
So we have
So charge on each sphere is -1.95 micro coulomb
Part b)
For first sphere
initial charge = 2.2 micro coulomb
final charge = -1.95 micro coulomb
excess charge = -1.95 - 2.2 = -4.15 micro coulomb
Q = Ne
For second sphere
initial charge = 4.2 micro coulomb
final charge = -1.95 micro coulomb
excess charge = -1.95 - 4.2 = -6.15 micro coulomb
Q = Ne
For third sphere
initial charge = -7.4 micro coulomb
final charge = -1.95 micro coulomb
absent charge = -1.95 + 7.4 = 5.45 micro coulomb
Q = Ne
For third sphere
initial charge = -6.8 micro coulomb
final charge = -1.95 micro coulomb
absent charge = -1.95 + 6.8 = 4.85 micro coulomb
Q = Ne