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Ymorist [56]
2 years ago
14

If the period of oscillation of a simple pendulum is 4s, find its length. If the velocity of the bob

Physics
1 answer:
Natalija [7]2 years ago
4 0

Answer:

Explanation:

Because we assume the pendulum is a "mathematical pendulum" (neglecting the moment of inertia of the bob), we can find:

T=2\pi\sqrt{\frac{L}{g}} \rightarrow 4=2\pi\sqrt{\frac{L}{9.81}} \rightarrow \frac{4}{\pi^{2}}=\frac{L}{9.81} \rightarrow L \approx 3.97 m

By using the y=A\sin(\omega t)  \rightarrow v = \frac{dy}{dt}=\omega A \cos\omega t = \omega\sqrt{A^{2}-y^{2}}

The mean position is the position when <em>y</em> = 0, so:

\omega = \frac{2\pi}{T}=\frac{2\pi}{4}=0.5\pi rad/s

and v = \omega A \rightarrow A=\frac{40}{0.5\pi}=\frac{80}{\pi} in centimeters (cm).

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80m, assuming g=10m/s^2

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The velocity of the current in a river has no effect on the the time it takes to paddle a canoe across the river, given that the boat is pointed perpendicular to the bank of the river, because

The velocity of the river does not change the velocity and therefore the distance traveled in the direction of the boat which is directed perpendicular to it

Reason:

Let \overset \rightarrow {v_y} represent the velocity of the boat across the river in the direction, \overset \rightarrow {d_y}, and let, \overset \rightarrow {v_x}, represent the velocity of the river, we have;

The velocity of the boat perpendicular to the direction of the river = \overset \rightarrow {v_y}

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This is so because the velocity in the perpendicular direction to the flow of

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  • The resultant velocity = \sqrt{(3 \ m/s)^2 + (4 \ m/s)^2} =5 \ m/s

The direction, θ, is given as follows;

\theta = \arctan \left(\dfrac{4}{3} \right) \approx 53.13^{\circ}

The length of the path of the boat, <em>l</em>, is given as follows;

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Considering only the y-components, we have;

t = \dfrac{w_y}{v_y}

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distance covered in the direction of the boat is unaffected by the velocity

of the river.

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