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Olegator [25]
3 years ago
12

Simplify: 2(4x + 8) (X) /h X X

Mathematics
1 answer:
jasenka [17]3 years ago
8 0

Answer:

x = -2

Step-by-step explanation:

2(4x+8)

= 8x+16

8x+16 = 0

-16 -16

8x = -16 (do -16÷8 & get)

x = -2

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Determine the center and radius of the following circle equation:<br> x2 + y2 – 10x + 8y + 40 = 0
antiseptic1488 [7]

Answer:

The center of this circle is (5, -4) and the radius is 1.

Step-by-step explanation:

First regroup these terms according to x and y :

x^2 - 10x + y^2 + 8y = -40

Next, complete the square for x^2 - 10x:  x^2 - 10x + 5^2 - 5^2.

and the same for y^2 + 8y:  y^2 + 8y + 16 - 16

Substituting these results into x^2 - 10x + y^2 + 8y = -40, we get:

x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40.

Next, rewrite x^2 - 10x + 25 and y^2 + 8y + 16 as squares of binomials:

Then x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40 becomes:

(x - 5)^2 + (y + 4)^2 - 25 - 16 = -40, or:

(x - 5)^2 + (y + 4)^2 = 1

This equation has the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius.  Matching like terms, we get h = 5, k = -4 and r = 1.

The center of this circle is (5, -4) and the radius is 1.

6 0
3 years ago
Read 2 more answers
In ΔJKL, k = 9.6 cm, l = 2.7 cm and ∠J=43°. Find ∠L, to the nearest 10th of a degree.
Bogdan [553]

Answer:

L = 10.64°

Step-by-step explanation:

From the given information:

In triangle JKL;

line k = 9.6 cm

line l = 2.7 cm; &

angle J = 43°

we are to find angle L = ???

We can use the sine rule to determine angle L:

i.e

\dfrac{j}{SIn \ J} = \dfrac{l}{ SIn \ L}

Using Pythagoras rule to find j

i,e

j² = k² + l²

j² = 9.6²+ 2.7²

j² = 92.16 + 7.29

j² = 99.45

j = \sqrt{99.45}

j = 9.97

∴

\dfrac{9.97}{Sin \ 43} = \dfrac{2.7}{ Sin \ L}

{9.97 \times    Sin (L ) = (2.7 \times Sin \ 43)

=  Sin \ L = \dfrac{ (2.7 \times Sin \ 43)}{9.97 } \\ \\ =  Sin \ L = \dfrac{ (2.7 \times 0.6819)}{9.97 }  \\ \\  = Sin \ L = 0.18466 \\ \\  L = Sin^{-1} (0.18466) \\ \\  L = 10.64 ^0

3 0
2 years ago
Verify that the points are the vertices of a parallelogram, and find its area. A(1, 1, 3), B(2, −5, 6), C(4, −2, −1), D(3, 4, −4
almond37 [142]

Answer:

Area = 71.3 sq unit

Step-by-step explanation:

a) We will use properties of parallelogram to verify the given vertices.

Property: Have a pair of parallel opposite sides

Hence, vectors AB AD BD BC CD AC. A pair should be parallel:

vectors

AB = A - B = (1, 1 , 3) - ( 2 , -5 , 6 ) = (-1 , 6 , -3)

AD = A - D = (1, 1 , 3) - (3, 4 , -4) = (-2 , -3 , 7)

BC = B - C = (2 , -5 , 6) - (4, -2 , -1) = (-2 ,-3 , 7)

CD = C - D = (4, -2 , -1) - (3, 4 , -4) = (1 , -6 , 3)

Hence we can see  that AB //CD and AD // BC as their unit vector co-efficents are identical/scalar multiple of each other.

b)

Equation of line AB = (1,1,3) + t*(-1 , 6 , -3 )

Point E = (1-t , 1+6t , 3 -3t) ... denotes an position of point E on line AB.

Choose a point on line CD, lets suppose C = ( 4 , -2 , -1 )

Vector EC = ( 1-t , 1+6t , 3-3t ) - (4 , -2 , -1 ) = (-3 -t , 3 +6t , 4 -3t)

For EC to be perpendicular to AB then dot product of AB . EC = 0

Hence,

EC . AB = -1 * (-3-t) -2*(3+6t) -3*(4-3t) = 0

3 + t -6 -12t -12+9t = 0

-2t-3 = 0

t = -3/2

Vector EC = (-3 -t , 3 +6t , 4 -3t) = (-1.5 , -6 , 8.5)

Area = magnitude (AB) * magnitude (EC)

Area = sqrt ((-1)^2 + 6^2 + (-3)^2) * sqrt ((-1.5)^2 + 6^2 + (8.5)^2)

Area = sqrt (46) * sqrt (442) / 2

Area = 71.3 unit^2

6 0
2 years ago
A water tank fills as shown in the graph below.
qaws [65]
I think the answer is 1/3 but i suck at slopes lol. Might wanna double check
8 0
2 years ago
Read 2 more answers
Nick invests $3,500 in an account earning 11% interest compounded annually. Krista invests $4,000 in an account earning 4% inter
Dovator [93]
Krista will have more money in 2 years time than Nick and she will get $14.05 more than Nick. Hope this helps.
7 0
3 years ago
Read 2 more answers
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