Question

Which of the following represents the ground state electron configuration for the Mn3 ion?

Answer 1

Answer:

$1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2$

Explanation:

The $Mn^{+3}$ has 22 electrons arround the nucleous. Its ground state configuration following the diagonal rule is:

$1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2$

In term of the previous noble gas:

$[Ar] 4s^2 3d^2$