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marusya05 [52]
3 years ago
14

Help me out please!!

Chemistry
1 answer:
malfutka [58]3 years ago
5 0

Answer:6.48*10^{-2}

Explanation:

alright, dawg, lets get this bread. CHEMISTRY? OH YEAH I LOVE CHEMISTRY.

what is a mol? do you know who avogadro is? sounds like avocado. free shavocado. ok so you MUST REMEMBER THIS NUMBER PLEASE.

please remember this number and commit it to your memory: avogadros number

6.02 * 10^{23}

this is how much a mole is. you know how a pair is 2 and a dozen is 12? ok so a mole is 6.02 * 10^{23} it is confusing at first but hopefully this helps you to understand.

now that we understand this..... lets perform this calculation with a calculator

(3.90 * 10^{22}) / (6.02 * 10^{23})

notice i divide the question by the avogadros number to find out how many moles are in the number. ok but listen... it gets into a tough area here... because HOW ARE WE TO DIVIDE SUCH A HUMONGOUS NUMBER BY ANOTHER HUMONGOUS NUMBER?!?!?

its easy, its cake, just listen this is how you do it. only focus on the numbers NOT the 10 exponential ones. so just 3.90 and 6.02 ok? lets divide these two numbers 3.90 / 6.02 and we get 0.6478... how interesting... ok now lets deal with the exponents of 10. notice that we are DIVIDING these numbers so think of it as subtracting the exponents of ten.....    22 minus 23 equals -1

so we have 0.6478 * 10^{-1}

now this negative 1 thing is annoying so lets just make it to the power of 0

0.06478 * 10^{0}

and anything to the power of 0 just becomes 1.

0.06478

so this is our answer but keep in mind we need 3 sig figs. if we round then we get 0.0648

put this into scientific notation we get 6.48*10^{-2}

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Answer:

\large \boxed{\text{197.4 g}}

Explanation:

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:     28.01               17.03

            N₂ + 3H₂ ⟶ 2NH₃

m/g:                          240.0

(a) Moles of NH₃

\text{Moles of NH}_{3} = \text{240.0 g NH}_{3}\times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}}= \text{14.09 mol NH}_{3}

(b) Moles of N₂

\text{Moles of N$_{2}$} = \text{14.09 mol NH}_{3} \times \dfrac{\text{1 mol N$_{2}$}}{\text{2 mol NH}_{3}} = \text{7.046 mol N$_{2}$}

(c) Mass of N₂

\text{Mass of N$_{2}$} =\text{7.046 mol N$_{2}$} \times \dfrac{\text{28.01 g N$_{2}$}}{\text{1 mol N$_{2}$}} = \textbf{197.4 g N$_{2}$}\\\\\text{The reaction requires $\large \boxed{\textbf{197.4 g}}$ of N$_{2}$}

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In water, mgcl2 dissociates into mg2+ and cl-. Based on this information what type of bond is involved in the formation of mgcl2
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<h3>Answer:</h3>

              Ionic Bond

<h3>Explanation:</h3>

                     Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

               Less than 0.4 then it is Non Polar Covalent  Bonding

               Between 0.4 and 1.7 then it is Polar Covalent  Bonding

               Greater than 1.7 then it is Ionic  Bonding

For Mg and Cl,

                   E.N of Chlorine             =   3.16

                   E.N of Magnesium        =   1.31

                                                             ________

                   E.N Difference                     1.85          (Ionic Bond)

<h3>Conclusion:</h3>

                   MgCl₂ being ionic in nature when dissolved in water dissociates into Magnesium and Chloride ions respectively.


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