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3 years ago

Which idea did john dalton include in his atomic theory

Chemistry

2 answers:

marysya [2.9K]3 years ago

8 0

Explanation:

Dalton's atomic theory is based on law of constant proportion and law of conservation of mass, which was the first to describe all matter in terms of their properties and atoms. It states that :

All matter are made up of atoms which are indestructible and indivisible.
All atoms of an element given, are identical in properties and mass.
The compounds are combination of two or more different atoms.
The chemical reaction is basically rearrangement of atoms.

Alexandra [31]3 years ago

5 0

Dalton's atomic theory proposed that all matter was composed of atoms, indivisible and indestructible building blocks. While all atoms of an element were identical, different elements had atoms of differing size and mass.

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Baking soda (NaHCO3) can be added to a fruit mix solution to create a carbonated drink. An example is the reaction between bakin

Gwar [14]

The molarity of the solution is the moles dissolved per liter. The volume of 0.8 M citric acid solution will be 74.16 mL.

<h3>What is molarity?</h3>

Molarity of the solution is the concentration that is given by the moles of the solute that are dissolved to make the solution in liters.

The chemical reaction between baking soda and citric acid is shown as:

C₆H₈O₇ + 3NaHCO₃ → Na₃C₆H₅O₇ + 3H₂O + 3CO₂

Given,

Molarity = 0.8 M

Mass of baking soda = 15 grams

The molar mass of baking soda = 84.007 g/mol

Moles of baking soda = 15 ÷ 84.007 = 0.178 moles

From the reaction, it can be said that 3 moles of baking soda are required to react with 1 mole of citric acid. So, 0.178 moles will need, 0.059 moles.

The volume of citric caid needed is calculated as:

M = moles ÷ volume

Volume (L) = 0.059 ÷ 0.8

= 0.07416 L

Volume is converted into mL as:

1 L = 1000 mL

0.07416 L = 74.16 mL

Therefore, 74.16 mL is the volume of citric acid needed.

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2 years ago

Which chemical equation is unbalanced? c o2 right arrow. co2 sr o2 right arrow. 2sro 6h2 3o2 right arrow. 6h2o h2 h2 o2 right ar

netineya [11]

The unbalanced equation is one in which the moles of atoms are not equal on both sides of the reaction.

<h3>What is a balanced chemical equation?</h3>

A balanced chemical equation is one in wgich the moles of atoms in the reactants side is equal to the moles of atoms on the product side.

The given equations of reaction is not clearly stated.

Therefore, the unbalanced equation is one in which the moles of atoms are not equal on both sides of the reaction.

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2 years ago

Vapor obtained by evaporating 0.495 grams of an unknown liquid is collected in a 127 mL flask. At 371 K, the pressure of the vap

lidiya [134]

Answer:

The molar mass in g/mol is 121.4 g/m

Explanation:

Let's apply the Ideal Gases Law to solve this:

P . V = n . R. T

V = 125 mL → 0.125L

P = 754 Torr

760 Torr ___ 1 atm

754 Torr ____ (754 / 760) = 0.992 atm

Moles = Mass / Molar mass

0.992 atm . 0.125L = (0.495 g / MM) . 0.082 . 371K

(0.992 atm . 0.125L) / (0.082 . 371K) = (0.495 g / MM)

4.07x10⁻³ mol = 0.495 g / MM

MM = 0.495 g / 4.07x10⁻³ mol → 121.4 g/m

3 0

3 years ago

What is the molarity of a solution of 14.0 g NH4Br in enough H2O to make 150 mL of solution?

kiruha [24]

The molarity of a solution equals to the mole number of the solute/the volume of the solution. For NH4Br, we know that the mole mass is 98. So the molarity is (14/98) mol /0.15 L=0.95 mol/L.

8 0

3 years ago

Read 2 more answers

Given:

bulgar [2K]

Answer:

The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

Explanation:

Given;

CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol

From the combustion reaction above, it can be observed that;

1 mole of methane (CH₄) released 890 kilojoules of energy.

Now, we convert 59.7 grams of methane to moles

CH₄ = 12 + (1x4) = 16 g/mol

59.7 g of CH₄ $= \frac{59.7}{16} = 3.73125 \ moles$

1 mole of methane (CH₄) released 890 kilojoules of energy

3.73125 moles of methane (CH₄) will release ?

= 3.73125 moles x -890 kJ/mol

= -3320.81 kJ

Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

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3 years ago