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Semmy [17]
3 years ago
6

It's not important to monitor your heart rate during moderate intensity activities. True False

Physics
2 answers:
Mama L [17]3 years ago
5 0
I think it is   False 

hope this helps :3
8_murik_8 [283]3 years ago
5 0

Answer:

FALSE

Explanation:

Monitoring heart rate is important in all physical activities. Some heart problems are silent and may manifest during increased physical effort, albeit moderate. Therefore, the practice of exercises should be authorized by a cardiologist and you should monitor your heart rate whenever possible. This is a simple matter now, as there are applications and wristbands that measure heart rate.

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The 'net' force acting on the box is (9 - 3) = 6 newtons
in the direction that Carlos is pushing.

Force = (mass) x (acceleration)

6 = (3) x (acceleration)

Divide each side by 3 :

<em>2 m/s² = acceleration</em>
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3 years ago
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n deep space, sphere A of mass 47 kg is located at the origin of an x axis and sphere B of mass 110 kg is located on the axis at
Volgvan

Answer:

a)-1.014x 10^{-7J

b)3.296 x  10^{-7J

Explanation:

For Sphere A:

mass 'Ma'= 47kg

xa= 0

For sphere B:

mass 'Mb'= 110kg

xb=3.4m

a)the gravitational potential energy is given by

U_{i = -GMaMb/ d

U_{i= - 6.67 x 10^{-11} x 47 x 110/ 3.4 => -1.014x 10^{-7J

b) at d= 0.8m (3.4-2.6) and U_{i=-1.014x 10^{-7J

The sum of potential and kinetic energies must be conserved as the energy is conserved.

K_{i + U_{i= K_{f + U_{f

As sphere starts from rest and sphere A is fixed at its place, therefore K_{i is zero

U_{i= K_{f + U_{f

The final potential energy is

U_{f= - GMaMb/d

Solving for 'K_{f '

K_{f = U_{i + GMaMb/d => -1.014x 10^{-7 + 6.67 x 10^{-11} x 47 x 110/ 0.8

K_{f = 3.296 x  10^{-7J

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3 years ago
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Answer:

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B: Sugar can be separated from the water by evaporating the water. This will leave large chunks of sugar.

C: Sugar gets spread out among the water.

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Hoped this helped! :)

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3 years ago
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1 - cytoplasm

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