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3 years ago

ASAPPP

Physics

2 answers:

katen-ka-za [31]3 years ago

8 0

Power is the rate at which work is done (2nd option)

frozen [14]3 years ago

5 0

Answer:

Power is the rate at which work is done.

Explanation:

The work done divided by total time taken is called power of an object. The SI unit of power is watts. It is denoted by W. Its expression is given by :

$P=\dfrac{W}{t}$

Since, W = F.d

$P=\dfrac{F\times d}{t}$

Since, $\dfrac{d}{t}=v$

$P=F\times v$

It is also equal to the product of force and velocity. Hence, the correct option is (c).

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How do you do to your question to see if its answered?

Jobisdone [24]

Answer:

Go in notifications, it'll show if it was answered. If it doesn't show that a person answered it, wait a while, someone might respond :)

Explanation:

On the Top right of your screen, theres a bell button. Click that and it will show all the notifications. it will also show if a person answered it.

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Hope this helped

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3 years ago

Read 2 more answers

An object that weighs 2.450 N is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period o

Viktor [21]

Answer:

Spring constant, k = 24.1 N/m

Explanation:

Given that,

Weight of the object, W = 2.45 N

Time period of oscillation of simple harmonic motion, T = 0.64 s

To find,

Spring constant of the spring.

Solution,

In case of simple harmonic motion, the time period of oscillation is given by :

$T=2\pi\sqrt{\dfrac{m}{k}}$

m is the mass of object

$m=\dfrac{W}{g}$

$m=\dfrac{2.45}{9.8}$

m = 0.25 kg

$k=\dfrac{4\pi^2m}{T^2}$

$k=\dfrac{4\pi^2\times 0.25}{(0.64)^2}$

k = 24.09 N/m

k = 24.11 N/m

So, the spring constant of the spring is 24.1 N/m.

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3 years ago

g The potential energy of a pair of hydrogen atoms separated by a large distance x is given by U(x)=−C6/x6, where C6 is a positi

Arisa [49]

Answer:

$F_x = -\frac{6 C_6}{2^7}$

Attractive

Explanation:

Data provided in the question

The potential energy of a pair of hydrogen atoms given by $\frac{C_6}{X_6}$

Based on the given information, the force that one atom exerts on the other is

Potential energy μ = $\frac{C_6}{X_6}$

Force exerted by one atom upon another

$F_x = \frac{\partial U}{\partial X} = \frac{\partial}{\partial X} (-\frac{C_6}{X^6})$

$F_x = \frac{\partial}{\partial X} (\frac{C_6}{X^6})$

$F_x = -\frac{6 C_6}{2^7}$

As we can see that the $C_6$ comes in positive and constant which represents that the force is negative that means the force is attractive in nature

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3 years ago

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