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GaryK [48]
3 years ago
15

Which of the following activities is most likely to result in nutrient pollution? a. cutting down trees b. pouring motor oil dow

n the drain c. excess fertilizer use d. none of the above Please select the best answer from the choices provided A B C D
Physics
2 answers:
gtnhenbr [62]3 years ago
7 0
Excess fertilizer use results in nutrient pollution by effecting the nutrition values of the plants we eat.

Cutting down trees more likely to result in air pollution by an increase in greenhouse gases.

Pouring oil in drain creates water pollution which is not a nutrient source.
Talja [164]3 years ago
7 0

The correct answer is:

c. excess fertilizer use  

Explanation:

Nutrient pollution, a form of water pollution, regards to pollution by extreme inputs of nutrients. It is the main cause of eutrophication of surface waters, in which excess nutrients, normally nitrogen or phosphorus, animate algal growth. Causes of nutrient pollution include surface runoff from farm fields and pastures, secretions from septic tanks and feedlots, and eruptions from combustion.

You might be interested in
Standing waves can ruin the acoustics of a concert hall if there is excessive reflection of the sound waves that the performers
Dmitrij [34]

Answer:

The answer to the questions is;

In terms of standing waves, the listener moves from a location with high amplitude to one with lower amplitude or vibration (anti-node to node)

The distance 4.1 cm is equivalent to λ/4

Explanation:

For standing waves we have is a stationary wave comprising of two opposite direction moving waves that have equal amplitude and frequency, resulting in the superimposition of the waves. As such certain points are fixed along the wave path that is the peaks amplitude of the wave oscillation is constant at a particular point. A node occurring at a point and an anti-node occurring at another fixed point

When the listener moves 4.1 cm he or she has left the anti-node to the node hence the faintness of the sound

The distance from the node to the anti-node is 1/4 wavelength, or 1/4×λ

Therefore 4.1 cm is λ/4

6 0
4 years ago
A school bus takes 0.53 hours to reach the school from your house. If the average speed of the bus is 19km/h, what is the displa
Artist 52 [7]
D = v*t= 19*0,53 = 10.07 km
5 0
3 years ago
Read 2 more answers
If a photon has frequency = 2.00 x 1014s-1 and the speed of light = 3.00 x 108ms-1, then what is its wavelength?
butalik [34]

Answer:

The photon has a wavelength of 1.5x10^{-6}m

Explanation:

The speed of a wave can be defined as:

v = \nu \cdot \lambda (1)

Where v is the speed, \nu is the frequency and \lambda is the wavelength.

Equation 1 can be expressed in the following way for the case of an electromagnetic wave:

c = \nu \cdot \lambda (2)              

 

Where c is the speed of light.    

Therefore, \lamba\lambda can be isolated from equation 2 to get the wavelength of the photon.

\lambda = \frac{c}{\nu} (3)

\lambda = \frac{3.00x10^{8}m/s}{2.00x10^{14}s^{-1}}

\lambda = 1.5x10^{-6}m

Hence, the photon has a wavelength of 1.5x10^{-6}m        

<em>Summary:  </em>

Photons are the particles that constitutes light.

3 0
4 years ago
A tennis ball travels the length of the court in 24 m in .5 seconds find its average speed
maxonik [38]
Speed= Distance/Time
Distance=24m
Time= 5seconds
Speed= 24/5= 4.8m/s
3 0
4 years ago
Read 2 more answers
Assume that the loop is initially positioned at θ=30∘θ=30∘ and the current flowing into the loop is 0.500 AA . If the magnitude
labwork [276]

Answer:\tau=1.03\times 10^{-4}\ N-m

Torque,

Explanation:

Given that,

The loop is positioned at an angle of 30 degrees.

Current in the loop, I = 0.5 A

The magnitude of the magnetic field is 0.300 T, B = 0.3 T

We need to find the net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field. We know that the torque is given by :

\tau=NIAB\ \sin\theta

Let us assume that, A=0.0008\ m^2

\theta is the angle between normal and the magnetic field, \theta=90^{\circ}-30^{\circ}=60^{\circ}

Torque is given by :

\tau=1\times 0.5\ A\times 0.0008\ m^2\times 0.3\ T\ \sin(60)\\\\\tau=1.03\times 10^{-4}\ N-m

So, the net torque about the vertical axis is 1.03\times 10^{-4}\ N-m. Hence, this is the required solution.

4 0
3 years ago
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