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GaryK [48]
3 years ago
15

Which of the following activities is most likely to result in nutrient pollution? a. cutting down trees b. pouring motor oil dow

n the drain c. excess fertilizer use d. none of the above Please select the best answer from the choices provided A B C D
Physics
2 answers:
gtnhenbr [62]3 years ago
7 0
Excess fertilizer use results in nutrient pollution by effecting the nutrition values of the plants we eat.

Cutting down trees more likely to result in air pollution by an increase in greenhouse gases.

Pouring oil in drain creates water pollution which is not a nutrient source.
Talja [164]3 years ago
7 0

The correct answer is:

c. excess fertilizer use  

Explanation:

Nutrient pollution, a form of water pollution, regards to pollution by extreme inputs of nutrients. It is the main cause of eutrophication of surface waters, in which excess nutrients, normally nitrogen or phosphorus, animate algal growth. Causes of nutrient pollution include surface runoff from farm fields and pastures, secretions from septic tanks and feedlots, and eruptions from combustion.

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Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric
Goshia [24]

Complete Question:

Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric force on sphere B due to sphere A is F . F. The magnitude of the electric force on sphere A due to sphere B must be:

A. 2F

B. F/4

C. F/2

D. F

E. 4F

Answer:

D.

Explanation:

If both spheres can be treated as point charges, they must obey the Coulomb's law, that can be written as follows (in magnitude):

F =\frac{kQ*2Q}{r^{2} }

As it can be seen, this force is proportional to the product of the charges, so it must be the same for both charges.

As this force obeys also the Newton's 3rd Law, we conclude that the magnitude of the electric force on sphere A due to sphere B, must be equal to the the magnitude of the force on the sphere B due to the sphere A, i.e., just F.

3 0
3 years ago
Be-36 what hull type is best for use on ponds, small lakes and calm rivers?
LenaWriter [7]
The hull type that is best for use on ponds, small lakes and calm rivers is Flat Bottom Hull. 
A flat bottomed boat is a boat with a flat bottomed, two-chined hull, which allows it to be used in shallow bodies of water, such as rivers, because it is less likely to ground. The flat hull also makes the boat more stable in calm water. 
8 0
3 years ago
Read 2 more answers
When you drop a 0.43 kg apple, Earth exerts
Archy [21]

Answer:

The acceleration of the earth is 7.05 * 10^-25 m/s²

Explanation:

<u>Step 1:</u> Data given

mass of the apple = 0.43 kg

acceleration = 9.8 m/s²

mass of earth = 5.98 * 10 ^24 kg

<u>Step 2:</u> Calculate the acceleration of the earth

Following the third law of Newton F = m*a

F(apple) = F(earth) = m(apple)*a(apple)

F(apple) = 0.43 kg * 9.8 m/s² = 4.214 N

a(earth) = F(apple/earth)/m(earth)

a(earth) = 4.214N /5.98 * 10 ^24 kg

a(earth) = 7.05 * 10^-25 m/s²

The acceleration of the earth is 7.05 * 10^-25 m/s²

4 0
3 years ago
U NICIUN
Natasha_Volkova [10]
Answer B would be the correct answer for the questions

5 0
3 years ago
A 2.0 µF capacitor is charged through a 50,000 ohm resistor. How long does it take for the capacitor to reach 90% of full charge
Nesterboy [21]

Answer:

0.23 s

Explanation:

First of all, let's find the time constant of the circuit:

\tau=RC

where

R=50,000 \Omega is the resistance

C=2.0\mu F=2.0\cdot 10^{-6}F is the capacitance

Substituting,

\tau=(50,000 \Omega)(2.0\cdot 10^{-6}F)=0.1 s

The charge on a charging capacitor is given by

Q(t)=Q_0 (1-e^{-t/\tau} ) (1)

where

Q_0 is the full charge

we want to find the time t at which the capacitor reaches 90% of the full charge, so the time t at which

Q(t)=0.90 Q_0

Substituting this into eq.(1) we find

0.90 Q_0 = Q_0 (1-e^{-t/\tau})\\0.90=1-e^{-t/\tau}\\e^{-t/\tau}=1-0.90=0.10\\-\frac{t}{\tau}=ln(0.10)\\t=-\tau ln(0.10)=(0.1 s)ln(0.10)=0.23 s

4 0
3 years ago
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