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Georgia [21]
3 years ago
8

One year there was a total of 73 commercial and noncommercial orbital launches worldwide. In​ addition, the number of noncommerc

ial orbital launches was one more than three times the number of commercial orbital launches. Determine the number of commercial and noncommercial orbital launches.
Mathematics
1 answer:
Schach [20]3 years ago
7 0
The were 24 commercial launches and and 49 non commercial
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I am in 9th grade,if you have 889,865x999,786 what doe it equal also yes i am not in virtual school and teacher will not let me
RSB [31]

Answer:

889674568890

Step-by-step explanation:

I used a calculator :)

6 0
3 years ago
Please help please please
monitta

Answer:

x=10

y=-2

(10,-2)

Step-by-step explanation:

If X=10, we can put 10 in for x in the equation.

30 + 5y = 20

Next, we need to solve to find y.

We will get y on its own so we subtract 30 from 20 to get

5y=-10

We then know that 5 goes into -10 -2 times.

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3 years ago
How to solve 8/x^2-1=6/x+1
NARA [144]
You first need to cross multiply to get 8x+8=6x^2-6. Then make the function into 6x^2-8x-14=0 which can be simplified into 3x^2-4x-7=0 by dividing the equation by 2. Then you must split the middle(-4x) to get 3x^2+3x-7x-7=0. This simplifies to 3x(x+1)-7(x+1)=0 and then to (3x-7)(x+1)=0. From here you just solve for each root which you will find are x= -1 and 7/3
8 0
3 years ago
4(v + 8) = 40
Musya8 [376]
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3 years ago
Read 2 more answers
B-3a=2 3B- 6a=12 solve algebraicly show steps
lora16 [44]
B - 3A = 2
3B - 6A = 12

(2)B - (6)A =4
3B - 6A = 12

Subtract

-B = -8
B = 8

Plugin 8 for B

8 - 3A = 2
8 = 3A + 2
6 = 3A
2 = A

(Double checking)
3(8) - 6A = 12
-6A = 12-24 = -12
- 6A = -12
Divide by -6
A= 2
It works

A = 2. B = 8. Hope this helps
3 0
3 years ago
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