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jek_recluse [69]
3 years ago
7

A leaky faucet drips once each second. at this rate, it takes 1 hour to fill a 1-liter graduated cylinder to the 200-cm3 mark. w

hat unit conversion do you need in order to calculate the average volume of a single drop in cm3?
Physics
1 answer:
UNO [17]3 years ago
8 0
Define
v = volume of a drop per second, cm³/s

The time taken to fill 200 cm³ is 1 hour.
Let V = 200 cm³, the filled volume.
Let t = 1 h = 3600 s, the time required to fill the volume.

Therefore,
\frac{200 \,  cm^{3}}{v \, cm^{3}/s}  = 3600 \, s \\ v =  \frac{200}{3600} =0.0556 \, cm^{3}

The average volume of a single drop is approximately 0.0556 cm³.

Answer: 0.0556 cm³

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V₀ = NABω

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V₀ = NABω and ω = 2πf = 2π/t

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