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jek_recluse [69]
3 years ago
7

A leaky faucet drips once each second. at this rate, it takes 1 hour to fill a 1-liter graduated cylinder to the 200-cm3 mark. w

hat unit conversion do you need in order to calculate the average volume of a single drop in cm3?
Physics
1 answer:
UNO [17]3 years ago
8 0
Define
v = volume of a drop per second, cm³/s

The time taken to fill 200 cm³ is 1 hour.
Let V = 200 cm³, the filled volume.
Let t = 1 h = 3600 s, the time required to fill the volume.

Therefore,
\frac{200 \,  cm^{3}}{v \, cm^{3}/s}  = 3600 \, s \\ v =  \frac{200}{3600} =0.0556 \, cm^{3}

The average volume of a single drop is approximately 0.0556 cm³.

Answer: 0.0556 cm³

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A 34n force is applied to a 213kg mass how much does the mass accelerate
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If a stone dropped into a well reaches the water's surface after 3.0 seconds, how far did the stone drop before hitting the wate
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<span>s= 0.5 at^2
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3 years ago
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Baseball player A bunts the ball by hitting it in such a way that it acquires an initial velocity of 1.3 m/s parallel to the gro
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Answer:

Explanation:

cSep 20, 2010

well, since player b is obviously inadequate at athletics, it shows that player b is a woman, and because of this, she would not be able to hit the ball. The magnitude of the initial velocity would therefore be zero.

Anonymous

Sep 20, 2010

First you need to solve for time by using

d=(1/2)(a)(t^2)+(vi)t

1m=(1/2)(9.8)t^2 vertical initial velocity is 0m/s

t=.45 sec

Then you find the horizontal distance traveled by using

v=d/t

1.3m/s=d/.54sec

d=.585m

Then you need to find the time of player B by using

d=(1/2)(a)(t^2)+(vi)t

1.8m=(1/2)(9.8)(t^2) vertical initial velocity is 0

t=.61 sec

Finally to find player Bs initial horizontal velocity you use the horizontal equation

v=d/t

v=.585m/.61 sec

so v=.959m/s

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3 years ago
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Please help have due very soon?thank you
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The answer is :78 I think
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