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Ilya [14]
3 years ago
11

What happened to the salt molecules when they were added to cold water

Chemistry
1 answer:
Nimfa-mama [501]3 years ago
8 0
Cooler water molecules are denser than warm water and will not allow much of the salt to dissolve
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Trisha and her lab partner were conducting a variety of experiments to produce gases: hydrogen, oxygen, and carbon dioxide. In o
GaryK [48]

<u>Given:</u>

Volume of HCl = 150 ml

Molarity of HCl = 0.10 M

<u>To determine:</u>

The # moles of HCl

<u>Explanation:</u>

The molarity of a solution is the number of moles of a solute dissolved in a given volume

In this case:

Molarity of HCl = moles of HCl/volume of the solution

moles of HCl = Molarity * volume = 0.10 moles.L-1 * 0.150 L = 0.015 moles

Ans: A)

Moles of HCl is 0.015

7 0
3 years ago
What type of energy does a person experience when jumping on a trampoline?
Fofino [41]

Answer:

Knetic

Explanation:

When you jump on a trampoline, your body has kinetic energy that changes over time. As you jump up and down, your kinetic energy increases and decreases with your velocity. Your kinetic energy is greatest, just before you hit the trampoline on the way down and when you leave the trampoline surface on the way up.

7 0
2 years ago
Which of the following methods would be the best method for separating oil from water?
vazorg [7]
Oil and water can separate by utilizing a separating funnel, oil and water are totally insoluble in one another. The water structures lower while the oil forms the upper layer.
8 0
3 years ago
How does a system at equilibrium respond to the addition of more reactant
grin007 [14]

Answer:

It favors the forward reaction.

Explanation:

According to Le Chatelier's Principle, when a system at equilibrium suffers a perturbation, the system will react in order to counteract the effect of such perturbation.

If more reactant is added, the system will try to decrease its concentration. It will do so by favoring the forward reaction, decreasing the concentration of the reactant  and increasing the concentration of the products, in order to re-establish the equilibrium.

7 0
4 years ago
15. If you dilute a 6 M solution of HCl from 5 mL to 50mL, what is the concentration of this new solution? (M1V1 = M2V2)
Andreyy89

Answer:

B) 0.6M

Explanation:

               I apologize in advance if it is not correct :l

The (M1V1= M2V2) is given for you to plug in the correct numbers so let's jot this down.

                    (M1*V1= M2*V2)

so they give us 6M which would be our (M1), from this we can also conclude that 5mL is also V1; ( if you notice the M1's and V1's are always found next to eachother). This leads us to our 50mL, this would be our V2 because the volume went from 5mL to 50mL. Now lets put this in order based on what we know.

M1= 6M                                (M1*V1= M2*V2)

V1= 5mL

M2= ?

V2= 50mL

now we plug in what we know into the equation to find the unknown (M2)

                   (6M*5mL= M2*50mL)

now we could do the long math, but I don't think your on brainly to do the hard way. so lets keep it simple!

                   We are going to put the 50mL under the (6M*5mL) for division.

                             \frac{(6M*5mL)}{(50mL)} This is honestly MUCH easier, than manually answering. you just put that in the calculator and it'll give you B) 0.6M

                 

   honestly though I might not know what I'm doing cuz im currently doing my test and decided to answer this question ;)

        Good Luck!

6 0
3 years ago
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