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sashaice [31]
2 years ago
5

El concepto cosmológico abarca todo lo relativo a la cosmología y, al unir este término con la metafísica sería posible una corr

ecta asociación la cual sería * 3 puntos
Physics
1 answer:
Solnce55 [7]2 years ago
5 0

La respuesta correcta para esta pregunta abierta es la siguiente.

No incluyes opciones, incisos, o alguna referencia específica para responder esta pregunta.

De ahí que responderemos en términos generales basándonos en nuestro conocimiento previo.

El concepto cosmológico abarca todo lo relativo a la cosmología y, al unir este término con la metafísica sería posible una correcta asociación la cual sería benéfica para ambos campos de conocimiento porque de esta manera se estarían complementando y enriqueciendo el uno al otro.

Cuando la ciencia -en este caso, la cosmología- acepte los conceptos metafísico que no tienen un sustento científico pero que sí contemplan alternativas en el mundo espiritual que son aceptadas por una innumerable cantidad de personas, entonces los expertos podrán plantear nuevas y diferentes posibilidades de entender los fenómenos que al día de hoy, carecen de una convincente explicación.

Tanto la cosmología como la metafísica podrían mostrarse más receptivos a las aportaciones de una y la otra, con objeto de poder aumentar las posibilidades de comprender un fenómeno. No necesariamente debe haber una teoría científica para poder avanzar en el conocimiento de algún tema. De ahí que las aportaciones metafísicas sean válidas como una alternativa de investigación.

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A 2137 kg car moving east at 12.91 m/s collides with a 3264 kg car moving north. The cars stick together and move as a unit afte
IRINA_888 [86]

Answer:

The speed of the 3264 kg car before collision is 6.32 m/s

Explanation:

Let first car, mass m₁, moving east be moving with velocity, v₁ and second car, mass m₂, moving north be moving with velocity, v₂. Let the velocity of the two cars after collision be v₃

In a Collison (whether elastic or inelastic), momentum is always conserved.

Momentum before collision = momentum after collision.

Momentum before collision = m₁v₁ + m₂v₂

v₁ = (12.91î) m/s in vector form, m₁ = 2137 kg

v₂ = ?, v₂ = (v₂j) m/s in vector form, m₂ = 3264 kg

Momentum before collision = (2137)(12.91î) + (3264)(v₂j) = (27590î + 3264v₂j) kgm/s

Momentum after collision = (total mass of the cars after collision) × (velocity of the stuck-together cars after collision)

Total mass of the cars after collision = m₁ + m₂ = 2137 + 3264 = 5401 kg

Velocity after collision, v₃ = 6.38 m/s In the N36.8°E direction, put in vector form,

v₃ = (6.38 cos 36.8°î + 6.38 sin 36.8°j)

v₃ = (5.11î + 3.82j) m/s

Momentum after collision = 5401 (5.11î + 3.82j) = (27590î + 20641.4j) kgm/s

Momentum before collision = momentum after collision.

(27590î + 3264v₂j) = (27590î + 20641.4j)

Comparing components

3264v₂ = 20641.4j

v₂ = 6.32 m/s

Hope this Helps!!!

6 0
3 years ago
A pendulum in motion can either swing from side to side or turn in a continuous circle. The point at which it goes from one type
Ierofanga [76]

The kind of equation that can be used to differentiate the kind of separatrix that shows change on motion is

H = 2g/l.

<h3>What is simple pendulum?</h3>

A simple pendulum can be defined as the equipment that displays an oscillatory motion when a mass is tied on a rope and is suspended from it.

The various movements that occur using a simple pendulum is translational ( side to side) or continuous circle (oscillatory motion).

The equation that show that a change from one type of motion to another is H = 2g/l.

Learn more about motion here:

brainly.com/question/453639

#SPJ1

6 0
1 year ago
A closely wound, circular coil with radius 2.50 cmcm has 740 turns. Part A What must the current in the coil be if the magnetic
Vika [28.1K]

Answer:

The current in the coil is 4.086 A

Explanation:

Given;

radius of the circular coil, R = 2.5 cm = 0.025 m

number of turns of the circular coil, N = 740 turns

magnetic field at the center of the coil, B = 0.076 T

The magnetic field at the center of the coil is given by;

B = \frac{N\mu_o I}{2R}

where;

μ₀ is permeability of free space = 4 x 10⁻⁷ m/A

I is the current in the coil

R is radius of the coil

N is the number of turns of the coil

The current in the circular coil is given by

B = \frac{N\mu_o I}{2R} \\\\I = \frac{2BR}{N\mu_o} \\\\I =\frac{2*0.076*0.025}{740*4\pi*10^{-7}} \\\\I = 4.086 \ A

Therefore, the current in the coil is 4.086 A

3 0
3 years ago
Brainliest if correct Question 8 of 10
kramer

Answer:

B

Explanation:

5 0
2 years ago
Read 2 more answers
A mass of 148 g stretches a spring 13 cm. The mass is set in motion from its equlibrium position with a downward velocity of 10
Charra [1.4K]

Answer:

u(t)=1.15 \sin (8.68t)cm

0.3619sec

Explanation:

Given that

Mass,m=148 g

Length,L=13 cm

Velocity,u'(0)=10 cm/s

We have to find the position u of the mass at any time t

We know that

\omega_0=\sqrt{\frac{g}{L}}\\\\=\sqrt{\frac{980}{13}}\\\\=8.68 rad/s

Where g=980 cm/s^2

u(t)=Acos8.68 t+Bsin 8.68t

u(0)=0

Substitute the value

A=0\\u'(t)=-8.68Asin8.68t+8.68 Bcos8.86 t

Substitute u'(0)=10

8.68B=10

B=\frac{10}{8.68}=1.15

Substitute the values

u(t)=1.15 \sin (8.68t)cm

Period =T = 2π/8.68

After half period

π/8.68 it returns to equilibruim

π/8.68 = 0.3619sec

6 0
3 years ago
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