Hello :
f(x) = sin²(x) +cos(x)
the dirivate is : f'(x) = 2sin(x) cos(x) -sin(x) because :
( sin²(x) )' = 2sin(x) cos(x) and (cos(x))' = - sin(x)
f'(x) = 0 : sin(x) (2cos(x) - 1) = 0
sin(x) = 0 : x = k <span>π k in Z
</span>2cos(x) - 1 =0 : 2cos(x) =1
cos(x) = 1/2 = cos( π /3)
x = π /3 +2k π or x = - π /3 +2k π
in intervall : <span> <span>[0
, 2π] :
k=0 : x= 0 f(0) = 1 ( </span></span>minimum<span>)
</span>k=1 : x = π f(π) = -1 (<span>minimum)
x= </span> π /3 f ( π /3 ) = 1.25 ( <span>maximum)</span>
Answer:
...none of them are correct, but if i had to choose, it'd be A.
Step-by-step explanation:
It would be D.
Because the slope is the same but the yint is different
M=y2-y1/x2-x1
m=-10-1/5+2
m=-11/7
Sorry I can't help these answers don't make any sense
