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jolli1 [7]
3 years ago
13

The diagram shows four different locations in an atom. A shaded circle is shown, labeled nucleus. Two small points labeled one a

nd three are shown inside this shaded circle. A lighter shaded concentric circle is shown with a radius more than double of the inner circle. A point labeled two is shown inside a section of this circle which does not overlap with the inner circle. A flower petal like shaded region is shown above and below these circles. A point labeled four is shown inside the lower petal. Which locations are likely to have subatomic particles that are constantly in motion?

Chemistry
2 answers:
olga_2 [115]3 years ago
5 0

Answer is: 2 and 4.

Protons and neutrons (1 and 3) are in nucleus.

Electrons (2 and 4) are moving in energy levels around nucleus.

The electron (symbol: e⁻) is a subatomic particle whose electric charge is negative one elementary charge.

Proton is a subatomic particle with a positive electric charge of +1e elementary charge.

pshichka [43]3 years ago
3 0
<h2>Answer : 2</h2><h3>Explanation :</h3>

The shaded area labeled as 2 is likely to have subatomic particle that are constantly in motion.

The subatomic particles of the atom that are constantly in motion are called as electrons. The probability of finding electrons in the region shaded and labeled as 2. Electrons are in continuous motion in orbits around the nucleus of the atom. Therefore, the answer is 2.

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Ill upvote please help
NARA [144]
Hello there.

<span>Find the average acceleration of a northbound subway train that slows from 12 m/s to 9.6 m/s in 0.9 s

</span><span>2.7 m/s2
</span>
3 0
4 years ago
When 42.5 g of benzamide (C7H7NO) are dissolved in 500 g of a certain mystery liquid X, the freezing point of the solution is 6.
LuckyWell [14K]

Answer:

21.3g of Fe(NO₃)₃ are required to produce the same depression in freezing point of solution.

Explanation:

Freezing point depression is a colligative property which indicates, in determined mixture, the freezing point of solution is lower that the freezing point of the solvent, according the amount of solute.

Formula is: ΔT = Kf . m . i

Kf is the cryoscopic constant, which is particular for each solvent. We do not have that data, so we need to find it out in order to solve the question:

ΔT = Freezing point of pure solvent - Freezing point of solution.

This data is known → 6.40°C

m, means molality, moles of solute in 1kg of solvent. Let's get the moles of benzamide: 42.5 g . 1mol / 121g = 0.351 moles

m = 0.351 mol / 0.5kg = 0.702 m

As benzamide is an organic compound i, = 1. i are the number of ions dissolved in solution. Let's find out Kf:

6.40°C = Kf . 0.702 m . 1

6.40°C /0.702m = 9.11 °C/m.

Let's go to the next question.

ΔT is the same → 6.40°C

But this is, an inorganic salt, a ionic salt: Fe(NO₃)₃ →  1Fe³⁺  + 3NO₃⁻

For this case, we have 1 mol of Iron(III) and 3 nitrates, so i = 4

Let's replace data: 6.40°C = 9.11 °C/m . m . 4

6.40°C / (9.11 m/°C . 4) = 0.176 m

This data represents that, in 1 kg of solvent we have 0.176 moles of nitrate.

Mass of solvent X required in this case is 0.500 kg, so, the moles that are contained are: 0.500 kg . 0.176 mol/kg = 0.088 mol

Let's determine the mass of salt: 0.088 mol . 241.85g /1mol = 21.3 g

5 0
3 years ago
You have been working to develop a new fictitious compound in the lab. Determine the amount in units of moles​ [mol] of 40 grams
Serhud [2]

Answer : The moles of given compound is, 0.064 mole

Explanation : Given,

Mass of given compound = 40 g

Atomic mass of X = 50 amu

Atomic mass of Y = 45 amu

Atomic mass of Z = 10 amu

First we have to calculate the molar mass of given compound.

The given compound formula is, X_5Y_7Z_6

Molar mass of X_5Y_7Z_6 = (5 × Atomic mass of X) + (7 × Atomic mass of Y) + (6 × Atomic mass of Z)

Molar mass of X_5Y_7Z_6 = (5 × 50) + (7 × 45) + (6 × 10) = 625 g/mol

Now we have to calculate the moles of given compound.

\text{Moles of given compound}=\frac{\text{Mass of given compound}}{\text{Molar mass of given compound}}

\text{Moles of given compound}=\frac{40g}{625g/mol}

\text{Moles of given compound}=0.064mol

Thus, the moles of given compound is, 0.064 mole

6 0
4 years ago
Compare how fast the rate of CO2 increase is in the last few hundred years with the rate of increase (or decrease, for that matt
Tcecarenko [31]

The rate of CO2 increase is in the last few hundred years is 10 times more with the rate of increase (or decrease, for that matter) in the preceding 400,000 years.

There are many possible reasons for this cause , some primary factors are listed below:

  1. Increase in population
  2. increased emission of green house gases, as we all know auto mobile industry is growing rapidly and this vehicles releases harmful gases like CO2, CO ,etc. and increases carbon % , this CO2 is a main gas component in green house effect.
  3. Deforestation, as the amount of plant decreases the CO2 present in atmosphere increases, plants uses CO2 and sun lite to make their food via photosynthesis.
  4. Increased emission of Industrial flue gases, etc.

Learn more about green house effect here...

brainly.com/question/19521661

#SPJ1

7 0
2 years ago
What volume of 1.75 M hydrochloric acid (HCl aq) must be diluted with water to prepare 0.500 L of 0.250 M hydrochloric acid?
Airida [17]

Answer:

V_1=0.0714L

Explanation:

Hello there!

In this case, since we need to dilute the 1.75-M HCl, and the total number of moles remain unchanged, we can write:

n_1=n_2

And in terms of volume and concentration:

C_1V_1=C_2V_2

Thus, we can solve for the volume of the concentrated HCl as shown below:

V_1=\frac{C_2V_2}{C_1}

Therefore, we plug in the data to get:

V_1=\frac{0.250M*0.500L}{1.75 M}\\\\V_1=0.0714L

Best regards!

7 0
3 years ago
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