Can someone please answer. There is a picture. It is only one question. Thank you so much!

The angle is to be reflected over the line shown. What would be the measure of the reflected angle?

WITCHER [35]

There is nothing here for anyone to work off, If you have a picture or screenshot that would be very nice!

4 0

3 years ago

To make 5 pizzas, 1/2 cup of flour is used a. How much flour is needed to make one pizza? b.. How many cups of flour are needed

pogonyaev

Answer:

for a single pizza 1/10 a cup

for 12 pizzas 1 1/5 a cup

you can make 56 pizzas with 5 2/3 cups.

Step-by-step explanation:

for 5 pizzas you need 1/2 cup of flour, so to find out how much you'll need for a single pizza you'll need to divide it with 5. 1/2÷5=1/10

for a dozen pizzas you'll need to multiply that with 12. 1/10x12=12/10=1 1/5

Then to find out how many can we make with 5 2/3 cups we'll divide it with that 1/10

56/10÷1/10= 56 pizzas

8 0

3 years ago

The blue lake trail is 11 3/8 miles long. Gemma has hiked 2 1/2 miles each hour for 3 hours. How far is she from the end of the

melomori [17]

In the question it is given that the length of the blue lake trail is 11 3/8 miles. In the question it is also given that Gemma has hiked for a total time of 3 hours and each hour she has hiked 2 1/2 miles.
Now coming to solving the problem we get:
Total length of blue lake trail = 11 3/8 miles
   = 91/8 miles
Distance hiked by Gemma in 1 hour = 2 1/2 miles
   = 5/2 miles
Then the total distance hiked by Gemma in 3 hours = (5/2) * 3
   = 15/2 miles
The distance left to cover the full trail = (91/8) - (15/2) miles
      = (91 - 60)/8 miles
   = 31/8 miles
   = 3 7/8 miles.
So Gemma is 31/8 miles or 3 7/8 miles from the end of the trail.

7 0

3 years ago

Quit smoking: In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.

Flauer [41]

Answer:

The p-value of the test is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

Step-by-step explanation:

Test if less than half of HIV-positive smokers have used a nicotine patch:

At the null hypothesis, we test if the proportion is of at least half, that is:

$H_0: p \geq 0.5$

At the alternative hypothesis, we test if the proportion is below 0.5, that is:

$H_1: p < 0.5$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that $\mu = 0.5, \sigma = \sqrt{0.5*(1-0.5)} = 0.5$

In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.

This means that $n = 444, X = \frac{202}{444} = 0.455$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.455 - 0.5}{\frac{0.5}{\sqrt{444}}}$

$z = -1.9$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.455, which is the p-value of z = -1.9.

Looking at the z-table, z = -1.9 has a p-value of 0.0287.

The p-value is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

5 0

3 years ago

What is the tangent ratio of angle y?

larisa [96]

The answer should be b

6 0

3 years ago