Because the Earth has 80 times as much mass as the moon has, and also because you, most likely, are somewhat closer to the Earth than to the moon.
Answer:
4.2 km
Explanation:
CAR A(velocity =20m/s to East)
In 1s, it covers 20m.
In 120s(2min),it covers20*120m.=2400m=2.4 km
CAR B(velocity =15m/s to west)
In 1s, it covers 15m.
In 120s, it covers 15*120m.=1800m=1.8km
Now, distance between the two cars after 2 minutes =2.4 km+1.8 km=4.2km
44/5 seconds to g<span>o from a complete stop to 44 km/h</span>
Horizontal distance between the bullet and the target (s) = 195 m
Horizontal velocity of the bullet (u) = 275 m/s
Time taken to cover the horizontal distance = ![\frac{Distance}{velocity}](https://tex.z-dn.net/?f=%5Cfrac%7BDistance%7D%7Bvelocity%7D)
Time taken (t) = ![\frac{195}{275}](https://tex.z-dn.net/?f=%5Cfrac%7B195%7D%7B275%7D)
t = 0.709 s
Now, in the vertical direction:
Initial velocity (u) = 0 m/s
Let the depth covered be h.
Time taken (T) = 0.709 s
Acceleration due to gravity (g) = 9.8 m/s^2
Now, using the seconds equation of motion:
![h = ut + \frac{1}{2}at^2](https://tex.z-dn.net/?f=h%20%3D%20ut%20%2B%20%5Cfrac%7B1%7D%7B2%7Dat%5E2)
![h = 0 +\frac{1}{2}\times 9.8 \times 0.709^2](https://tex.z-dn.net/?f=h%20%3D%200%20%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%209.8%20%5Ctimes%200.709%5E2)
h = 2.463 meters
Hence, the bullet will hit 2.463 meters below the target.