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konstantin123 [22]
3 years ago
11

Please Help Me on this!!!! I'll Mark Brainliest!!!!! Thanks!!!!!!

Chemistry
2 answers:
makvit [3.9K]3 years ago
8 0

Answer:

15.999amu

Explanation:

There is way more O16 than any other, so O17 and O18 affect it very little.

Stella [2.4K]3 years ago
5 0

Answer:

The answer is 15.999 amu

Explanation:

Data:

mO16 = 15.995 amu

mO17 = 16.999 amu

mO18 = 17.999 amu

%O16 = 99.757%

%O17 = 0.038%

%O18 = 0.205%

The molecular mass of oxygen is going to be equal to:

mO = \frac{(mO16xpercentO16)+(mO17xpercentO17)+(mO18xpercentO18)}{100}

replacing, we have:

mO = \frac{(15.995x99.757)+(16.999x0.038)+(17.999x0.205)}{100} = 15.999489 amu

this is approximately 15.999 amu

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How many formula units are present in 40.0 grams of Cu2S?
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How much calcium can be recovered from 75.0g of calcium fluoride
7nadin3 [17]

38.46g

Explanation:

Given parameters:

Mass of CaF₂ = 75.0g

Unknown:

Mass of calcium that can be recovered = ?

Solution:

This is a mass percentage problem and we need to solve it accordingly.

To solve this problem;

Find the molar mass of  CaF₂

Find the ratio between the molar mass of Ca and that of  CaF₂

Multiply by the given mass

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3 0
2 years ago
Some oxygen gas takes up a volume of 2.00 liters at 0.99 atm and 273 K. Its volume doubles and its temperature decreases to 137
nataly862011 [7]

Answer:

The answer to your question is : letter B. 0.25 atm

Explanation:

To solve this problem we need to use the combined gas law:

    <u>P₁V₁</u>   =    <u>P₂V₂</u>

      T₁              T₂

Data

P1 = 0.99 atm  V1 = 2 l  T1 = 273K

P2 = ?               V2 = 4 l   T2 = 137K

Now, the clear P2 from the equation and we get

       P2 = P1V1T2 / T1V2

Substitution         P2 = (2 x 0.99 x 137)/(273 x 4)

       P2 = 271.26 / 1092

Result       P2 = 0.248 atm ≈ 0.25 atm

5 0
3 years ago
Read 2 more answers
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