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svlad2 [7]
3 years ago
7

Which element is most likely to have an oxidation number of -2?

Chemistry
1 answer:
AnnZ [28]3 years ago
8 0

Answer:

D. O

_________________________________

F ----------¢ - 1

Ne --------¢ 0

Ca --------¢ + 2

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xz_007 [3.2K]
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I did this to the best of my ability. I have a hard time comprehending things sometimes so I’m so so so sorry if it’s wrong
8 0
3 years ago
Which step will decrease the pressure of a gas inside a closed cubical container? increasing the number of moles of gas decreasi
Jobisdone [24]

Answer: Decreasing the temperature inside the container will decrease the pressure of a gas inside a closed cubical container.

Explanation:

According to Gay-Lussac's Law : 'The pressure of the gas increases with increase in temperature of the gas when volume of the gas is kept constant'.

(Pressure)\propto (Temperature)

At constant volume, pressure of the gas will decrease on decreasing the temperature or vice versa.

Decreasing the temperature inside the container will decrease the pressure of a gas inside a closed cubical container.

8 0
3 years ago
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What is the mass of a 0.23 L substance, if it has density of 1.90 g/mL?
jolli1 [7]

Answer:

437 g

Explanation:

as mass = density × volume

8 0
3 years ago
Use mathematics to prove that the 5.50 grams of salicylic acid (C7H6O3) used in this experiment is equal to 0.04 mol.
g100num [7]

Answer:

Please find the answer to the question below

Explanation:

In chemistry, the following mathematical formula is used to calculate the number of moles contained by a substance:

mole = mass of substance (g)/molar mass of substance (g/mol)

Molar mass of salicylic acid (C7H6O3) = 12(7) + 1(6) + 16(3)

= 84 + 6 + 48

= 138g/mol

Mass = 5.50grams

mole = 5.5/138

mole = 0.039

Approximately, the number of moles of 5.5grams of salicylic acid is 0.04moles. This is in accordance with the mole value (0.04) given in this question.

7 0
3 years ago
Which lists only metalloids?
enot [183]

Answer:

boron (B), germanium (Ge), and tellurium (Te)

6 0
3 years ago
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