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tia_tia [17]
3 years ago
13

Consider the chart describing the element. According to the chart, the element is _______ with an atomic number of ___________.

A) neon; 3 B) boron; 4 C) lithium; 3 D) nitrogen; 7
Chemistry
1 answer:
GenaCL600 [577]3 years ago
4 0

C) lithium; 3

Explanation:

Considering the chart describing the element. According to the chart, the element is lithium with an atomic number of 3.

  • Atomic numbers are used on the periodic table to arrange elements in their proper place.
  • Atomic number is the number of protons in an atom.
  • This number is unique for every atom.
  • From the described chart, we see that the atom described is Lithium.
  • The atomic number of neon is 10, boron is 5.
  • Unless otherwise stated or shown, it can be nitrogen 7.

learn more:

Periodic table brainly.com/question/8543126

#learnwithBrainly

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3 years ago
The diameter of a hydrogen atom is 106 pm. Find the length in kilometers of a row of 4.34 x 1023 hydrogen atoms?
valina [46]

The length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.

<h3>Length of the entire hydrogen atoms</h3>

The length of the entire hydrogen atom is calculated as follows;

Length of the row = number x diameter of one

Length of the row = 4.34 x 10²³ x 10⁶ x 10⁻¹²

Length of the row = 4.34 x 10¹⁷ m

Length of the row = 4.34 x 10¹⁴ km

Thus, the length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.

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2 years ago
Sewage and industrial pollutants dumped into a body of water can reduce the dissolved oxygen concentration and adversely affect
MArishka [77]

Answer:

FALSE

Since 0.385 < 0.526, the value for week 3 is accepted.

Explanation:

Qexp = (|Xq - Xₙ₋₁|)/w

where Xq is the suspected outlier; Xₙ₋₁ is the next nearest data point; w is the range of data

First, the data are arranged in decreasing order, from highest to lowest:

3. 5.6

2. 5.1

8. 5.1

1. 4.9

6. 4.9

5. 4.7

7. 4.5

4. 4.3

Xq = 5.6; Xₙ₋₁ = 5.1; w = 5.6 - 4.3 = 1.3

Qexp = (|5.6 - 5.1|)/1.3 = 0.385

From tables, at 95% confidence level, for n = 8, Qcrit = 0.526

Since 0.385 < 0.526, the value for week 3 is accepted.

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