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soldier1979 [14.2K]
4 years ago
11

A compass in a magnetic field will line up __________.

Physics
1 answer:
Anastaziya [24]4 years ago
5 0
Line up in a direction parallel to the magnetic field lines<span />
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They are equal and opposite (action and reaction)
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For aerodynamic reasons, nearly all modern aircraft feature at leastone large vertical stabilizer. The B-2 "stealth" bomber pict
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Answer:

The reason why the B-2 "stealth" bomber has no vertical fins (or stabilizers) at all, is because by design, the vertical fins are not required to provide stability; the stability for yaw movement is provided through a computer that controls the B-2 stealth bomber; hence the B-2 stealth bomber does not need a vertical stabilizer in order to fly.

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3 years ago
a cannonball is fired with a speed of 76 m/s from the top of a cliff. It strikes the plane below with a speed of 89 m/s. if we n
galina1969 [7]

Assuming the cannonball is fired horizontally, its horizontal velocity stays at a constant 76 m/s. At the point it hits the ground, it has a speed of 89 m/s, so if its vertical velocity at that moment is v_y, we have

89\dfrac{\rm m}{\rm s}=\sqrt{\left(76\dfrac{\rm m}{\rm s}\right)^2+{v_y}^2}\implies{v_y}^2\approx2145\dfrac{\mathrm m^2}{\mathrm s^2}

(taking the negative square root because we take the downward direction to be negative)

Recall that

{v_f}^2-{v_i}^2=2a\Delta x

where v_i and v_f are the initial and final velocities, respectively; a is the acceleration; and \Delta x is the change in position of a body. In the cannonball's case, it starts with 0 vertical velocity and is subject to a downward acceleration with magnitude g=9.80\frac{\rm m}{\mathrm s^2}. So we have

2145\dfrac{\mathrm m^2}{\mathrm s^2}-0=-2g\Delta y\implies\Delta y\approx-109.44\,\mathrm m

(which is negative because we take the cannonball's starting position at the top of the cliff to be the origin) so the cliff is about 109 m high.

8 0
3 years ago
What is the period, in seconds, that corresponds to each of
Charra [1.4K]

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0.1s,5s,0.017s

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7 0
3 years ago
If a resistor of 6 kohms is rated at a maximum power dissipation of 0.5 watts, what is the maximum current it can safely handle
vichka [17]

Answer : The maximum current will be, 9.13\times 10^{-3}A

Explanation :

The relationship between power, resistance and current is:

P=I^2\times R

where,

P = power = 0.5 watts

I = current = ?

R = resistance = 6 kohms = 6000 ohms

Now put all the given values in the above formula, we get:

0.5=I^2\times 6000

I=9.13\times 10^{-3}A

Thus, the maximum current will be, 9.13\times 10^{-3}A

8 0
4 years ago
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