The primary force would be Thermal Convection, it pushes it and thus makes continents drift.
-Hope that helps, Nexxmexx :3
Answer:
r = 6.5*10^-3 m
Explanation:
I'm assuming you meant to ask the diameters of the disk, if so, here's it
Given
Quantity of charge on electron, Q = 1.4*10^9
Electric field strength, e = 1.9*10^5
q = Q * 1.6*10^-19
q = 2.24*10^-10
E = q/ε(0)A, making A the subject of formula, we have
A = q / [E * ε(0)], where
ε(0) = 8.85*10^-12
A = 2.24*10^-10 / (1.9*10^5 * 8.85*10^-12)
A = 2.24*10^-10 / 1.6815*10^-6
A = 1.33*10^-4 m²
Remember A = πr²
1.33*10^-4 = 3.142 * r²
r² = 1.33*10^-4 / 3.142
r² = 4.23*10^-5
r = 6.5*10^-3 m
Answer:
She must be launched with minimum speed of <u>57.67 m/s</u> to clear the 520 m gap.
Step-by-step explanation:
Given:
The angle of projection of the projectile is,
°
Range of the projectile is,
m.
Acceleration due to gravity, ![g=9.8\ m/s^2](https://tex.z-dn.net/?f=g%3D9.8%5C%20m%2Fs%5E2)
The minimum speed to cross the gap is the initial speed of the projectile and can be determined using the formula for range of projectile.
The range of projectile is given as:
![R=\frac{v_{0}^2\sin2\theta}{g}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7Bv_%7B0%7D%5E2%5Csin2%5Ctheta%7D%7Bg%7D)
Plug in all the given values and solve for minimum speed,
.
![520=\frac{v_{0}^2\sin(2(65))}{9.8}\\520\times 9.8=v_{0}^2\sin(130)\\5096=1.532v_{0}^2\\v_0^2=\frac{5096}{1.532}\\v_0^2=3326.371\\v_0=\sqrt{3326.371}=57.67\textrm{ m/s}](https://tex.z-dn.net/?f=520%3D%5Cfrac%7Bv_%7B0%7D%5E2%5Csin%282%2865%29%29%7D%7B9.8%7D%5C%5C520%5Ctimes%209.8%3Dv_%7B0%7D%5E2%5Csin%28130%29%5C%5C5096%3D1.532v_%7B0%7D%5E2%5C%5Cv_0%5E2%3D%5Cfrac%7B5096%7D%7B1.532%7D%5C%5Cv_0%5E2%3D3326.371%5C%5Cv_0%3D%5Csqrt%7B3326.371%7D%3D57.67%5Ctextrm%7B%20m%2Fs%7D)
Therefore, she must be launched with minimum speed of 57.67 m/s to clear the 520 m gap.
They are almost the same temperature!!
Answer:
T = 3990 N
Explanation:
The free body diagram for the elevator consists of a tension force pointing up, and its weight pointing down. So the elevator's net force is:
F = T - 2940N
ad at the same time, using Newton's second law, we have that this net force should equal the elevator's mass (300 kg) times its acceleration (a):
T - 2940N = 300kg (3.5m/s^2)
then
T = 2940 N + 1050 N
T = 3990 N