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2 years ago

Having so much trouble with this : which fact represents evidence for the big bang theory

Physics

1 answer:

Ivan2 years ago

3 0

Answer:

Every object located in the universe emits radiation.

Explanation:

This is the fact which represents evidence of The Big Bang Theory.

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A baseball is hit into the air with a velocity of 27 m/s. How high does it go?

Marizza181 [45]

Answer:

Explanation:

If a baseball is hit into the air with a velocity of 27 m/s, we want to determine the maximum height of the ball. Using the projecile formula;

Max height H = u²/2g

u is the initial velocity of the body = 27m/s

g is the acceleration due to gravity = 9.81m/s²

H = 27²/2(9.81)

H = 729/19.62

H = 37.16m

Hence the ball went 37.16m high

8 0

3 years ago

Which of the following are properties of mechanical waves?

yuradex [85]

The properties of mechanical waves are : ( C and D )

The three categories of mechanical waves are transverse, longitudinal,surface waves ( C )
Waves transport energy,but not matter ( D )

<h3>What are mechanical waves ?</h3>

Mechanical waves are a category of waves which cannot transmit energy through a vacuum, i.e. they require a medium to transmit their energy from one end to another. An example of a mechanical wave is : sound wave. Mechanical waves are grouped into transverse, longitudinal and surface waves.

Hence we can conclude that The properties of mechanical waves are : The three categories of mechanical waves are transverse, longitudinal,surface waves and Waves transport energy,but not matter

Learn more about mechanical waves : brainly.com/question/26116832

#SPJ1

6 0

2 years ago

A person uses 750 kcal on a long walk calculate the energy used for the walk in kilojoules

guapka [62]

Basically, this problem asks you to convert kilocalories (kcal) to kilojoules (kJ). Both are units of energy. To convert kcal to kJ, the equivalence is: 1 kcal = 4.184 kJ. Through dimensional analysis, the solution is as follows:

750 kcal * 4.184 kJ/1 kcal = 3,138 kJ

6 0

4 years ago

Why is sun the only star that can be seen during day time

hoa [83]

Explanation:

i think the sun is near the earth that's why we see the sun during the day and the moon is behind the sun so when it is in the night the moon will remove in front the sun and there will be night I hope it will help you

7 0

3 years ago

An electron is released from rest in a uniform electric field. The electron accelerates vertically upward, traveling 4.50 m in t

Liono4ka [1.6K]

(a) 5.69 N/C, vertically downward

We can calculate the acceleration of the electron by using the SUVAT equation:

$d=ut+\frac{1}{2}at^2$

where

d = 4.50 m is the distance travelled by the electron

u = 0 is the initial velocity of the electron

$t=3.00 \mu s = 3.0 \cdot 10^{-6} s$ is the time of travelling

a is the acceleration

Solving for a,

$a=\frac{2d}{t^2}=\frac{2(4.50)}{(3.0\cdot 10^{-6})^2}=1.0\cdot 10^{12} m/s^2$

Given the mass of the electron,

$m=9.11\cdot 10^{-31} kg$

We can find the electric force acting on the electron:

$F=ma=(9.11\cdot 10^{-31})(1.0\cdot 10^{12})=9.11\cdot 10^{-19}N$

And the electric force can be written as

$F=qE$

where

$q=-1.6\cdot 10^{-19}C$ is the charge of the electron

E is the magnitude of the electric field

Solving for E,

$E=\frac{F}{q}=\frac{9.11\cdot 10^{-19}}{-1.6\cdot 10^{-19}}=-5.69 N/C$

The negative sign means that the direction of the electric field is opposite to the direction of the force (because the charge is negative): since the force has same direction of the acceleration (vertically upward), the electric field must point vertically downward.

(b) Yes

We can answer the question by calculating the magnitude of the gravitational force acting on the electron, to check if it is relevant or not. The gravitational force on the electron is:

$F=mg$

where

$m=9.11\cdot 10^{-31} kg$ is the mass of the electron

$g=9.81 m/s^2$ is the acceleration due to gravity

Substituting,

$F=(9.11\cdot 10^{-31})(9.81)=8.93\cdot 10^{-30}N$

We see that the gravitational force is basically negligible compared to the electric force calculated in part (a), therefore we can say it is justified to ignore the effect of gravity in the problem.

7 0

4 years ago