Question

A light ray in air hits piece of quartz at a 39.0 deg angle. Inside the quartz, the light slows down to 2.06*10^8 m/s. At what angle does the light travel in the quarts? (Hint: find n.)
(Unit=deg)

Answer 1

Answer:

Angle of light at which it will travel in the quartz is given as

$\theta = 25.6^o$

Explanation:

As we know that the refractive index of a medium is the ratio of speed of light in air and speed of light in the medium

So we will have

$\mu = \frac{c}{v}$

here we have

$\mu = \frac{3 \times 10^8}{2.06 \times 10^8}$

$\mu = 1.456$

now by Snell's law we have

$n_1 sin\theta_1 = n_2 sin\theta_2$

$1 sin39 = 1.456 sin\theta$

$\theta = 25.6^o$