Answer:
A
Explanation:
When you pull the string the weight will experience a downward force and come closer to the vertical tube. And the angle between weight and hand through string is decreased so the angular velocity decreases
Answer:
588 J
Explanation:
PE (potential energy) = (mass) x (gravity) x (height)
mass = 12 kg
gravity = 9.8m/s^2
height = 5 m
PE = (12) x (9.8) x (5) = 588 J (Joules)
Answer:
Explanation:
Given that,
Mass of first car
M1= 328kg
The car is moving in positive direction of x axis with velocity
U1 = 19.1m/s
Velocity of second car
U2 = 13m/s, in the same direction as the first car..
Mass of second car
M2 = 790kg
Velocity of second car after collision
V2 = 15.1 m/s
Velocity of first car after collision
V1 =?
This is an elastic collision,
And using the conservation of momentum principle
Momentum before collision is equal to momentum after collision
P(before) = P(after)
M1•U1 + M2•U2 = M1•V1 + M2•V2
328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1
16534.8 = 328•V1 + 11929
328•V1 = 16534.8—11929
328•V1 = 4605.8
V1 = 4605.8/328
V1 = 14.04 m/s
The velocity of the first car after collision is 14.04 m/s
The work that is done when twice the load is lifted twice the distance is
four times as much
The net work performed by forces acting on an object equals the change in kinetic energy, according to the work-energy theorem.
when an item slows down, the net work applied to it decreases, its change in kinetic energy is negative, and its ultimate kinetic energy is less than its starting kinetic energy. When an item accelerates, positive net work is done on it. All the forces acting on an item must be taken into consideration when determining the net work. You will obtain an incorrect result if you exclude any forces that affect an item or if you add any forces that do not affect it.
Hence The work that is done when twice the load is lifted twice the distance is four times as much
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<span>assuming the pitch is 100yards long, the player runs 100yards to the other goal then a further 50 yards back to the 50-yard line. So he/she runs 150yards in 18s
150/18 = 8.33yards per second average speed.
Initial velocity = 0, average velocity =8.33
Vav = (Vinitial+Vfinal)/2
Vav = 4.16m/s</span>
