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Anna35 [415]
3 years ago
10

Two rocks are at the top of a building. Rock 1 is dropped from rest while Rock 2 is thrown horizontaly at a velocity of 5 ms.

Physics
1 answer:
LuckyWell [14K]3 years ago
7 0

Answer:

I'm pretty sure the answer is 0 m/s²

Explanation:

The horizontal velocity of the second rock is 5 m/s, so if we pretend air resistance doesn't exist, it will maintain that horizontal velocity, meaning that there is no horizontal acceleration.

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Contrast the average speed and the instantaneous speed of runner in a race.
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Average speed of the runner is the rate at which the runner covers the total distance. Average speed of the runner in the race is given by,

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Where

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Total time = time taken by the runner to cover entire distance

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Instantaneous speed = \frac{dx}{dt}

x = position of the runner at time t

t = time taken to cover distance x

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a painting in an art gallery has height h and is hung so that its lower edge is a distance d above the eye of an observer. How f
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Solution:

With reference to Fig. 1

Let 'x' be the distance from the wall

Then for \DeltaDAC:

tan\theta = \frac{d}{x}

⇒ \theta = tan^{-1} \frac{d}{x}

Now for the \DeltaBAC:

tan\theta = \frac{d + h}{x}

⇒ \theta = tan^{-1} \frac{d + h}{x}

Now, differentiating w.r.t x:

\frac{d\theta }{dx} = \frac{d}{dx}[tan^{-1} \frac{d + h}{x} -  tan^{-1} \frac{d}{x}]

For maximum angle, \frac{d\theta }{dx} = 0

Now,

0 = [/tex]\frac{d}{dx}[tan^{-1} \frac{d + h}{x} -  tan^{-1} \frac{d}{x}][/tex]

0 = \frac{-(d + h)}{(d + h)^{2} + x^{2}} -\frac{-d}{x^{2} + d^{2}}

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