How many formula units are there in 20.6 moles of Al(NO3)3?

A protein that binds to glutathione can be purified using an affinity column where the solid phase is a cellulose matrix covalen

miskamm [114]

Answer:

High concentration of glutathione should be included in the elution buffer for the given experiment to remove protein from the column.

Explanation:

Affinity chromatography is one of important biochemical technique of chromatography which depends on the affinity of ligand for the receptor.Here the ligand is a protein mixture which act as mobile phase and the receptor is present in the wall of chromatography column act as stationary phase.When the protein mixture is applied on the top of the column the substances present within the protein that have high affinity for the receptor present in the walls of chromatography column binds to the later but rest of the protein pass away through the column.High concentration of ligand is used within an buffer solution to remove the desired protein from the column.

From this point of view it can be stated that in the given question high concentration of glutathione should be used to remove the desired protein from the column.

7 0

3 years ago

What is the speed of an electron that has a de Broglie wavelength of 100. nm?

Advocard [28]

Answer: The speed of the electron is $7.24\times 10^3m/s$

Explanation:

To calculate the speed of electron for given wavelength, we use the equation given by De-Broglie's, which is:

$\lambda=\frac{h}{mv}$

where,

$\lambda$ = De-Broglie's wavelength = $100nm=100\times 10^{-9}m$

h = Planck's constant = $6.6\times 10^{-34}Js$

m = mass of the electron = $9.11\times 10^{-31}kg$

v = speed of the electron = ?

Putting values in above equation, we get:

$100\times 10^{-9}m=\frac{6.6\times 10^{-34}Js}{9.11\times 10^{-31}kg\times v}\\\\v=\frac{6.6\times 10^{-34}Js}{9.11\times 10^{-31}kg\times 100\times 10^{-9}m}=7.24\times 10^3m/s$

Hence, the speed of the electron is $7.24\times 10^3m/s$

4 0

3 years ago

35 POINTS Y'ALL

jasenka [17]

Answer:

:)

Explanation:

Petroleum gas is mainly C3 and C4 based (propane and butane), whilst natural gas is predominantly C1 and C2 (methane and ethane). Petroleum gas is generally produced via the cracking of naphtha, which is one of the components separated during crude oil refining.

5 0

3 years ago

Read 2 more answers

If there are 1,000 mg in 1 gram. Then how many mg are in 2.5 grams?

mihalych1998 [28]

Answer:

1 gram =1000mg

Explanation:

Then 2.5g=2.5*1000

2500mg

7 0

3 years ago

Consider the balanced chemical reaction when phosphorus and iodine react to produce phosphorus triodide: 2 P(s) + 3 I2(g) → 2 PI

melamori03 [73]

Answer:

Percent yield of PI3 = 95.4%

Explanation:

This is the reaction:

2P (s) + 3I2 (g) > 2PI3 (g)

Let's determine the moles of iodine that has reacted.

58.6 g / 253.8 g/mol = 0.231 mol

Ratio is 3:2. Let's make a rule of three to state the moles produced at 100 % yield reaction.

3 moles of I2 react to make 2 moles of PI3

0.231 moles of I2 would make (0.231 .2) / 3 = 0.154 moles of PI3

As we have produced 0.147 moles let's determine the percent yield.

(Yield produced / Theoretical yield) . 100 > (0.147 / 0.154) . 100 = 95.4%

5 0

3 years ago